Answer: 3.27kg
Explanation:
Inertia can be said to be the resistance of an object to a change in its motion. This includes a change in its direction. An object will stay still or keep moving at the same speed and in a straight line, except it is acted upon by an unbalanced external force.
Given F = 30N
r = 0.14m
a = 130rad/s²
Then, T = Fr
T = 30*0.14
T = 4.2Nm
Also, T = inertia * acceleration
Inertia = 4.2/a
Inertia = 4.2/130
Inertia = 0.032
Also, inertia = mr²/2
0.032 = m * (0.14²)/2
0.032 = m * 0.0098
m = 0.032/0.0098
m = 3.27kg
Answer:
400.7886829 rad/s
Explanation:
First we have to turn our 0.35 rev/s into rad/s using the equation
(Xrev/s)*2pi=Xrad/s we can plug in .35*2pi=.7pi rad/s
Now we can us the equation m_1*v_1*r_1^2=m_1*v_2*r_2^2 we can plug in the given. Because the mass remains the same we can cross it off of both sides giving us just: v_1*r_1^2=v_2*r_2^2
(.7pi)*(.54)^2=(v_2)*(.04)^2
(.20412pi)=(v_2)*(.0016) [.20412pi=.6412618925]
then using division on both sides we get
(.6412618925/.0016)=v_2=400.79rad/s(This answer is rounded to the nearest hundreth)
See you in Mr.K's class tomorrow! -Ruben
Question seems to be missing. Found it on google:
a) How long is the ski jumper airborne?
b) Where does the ski jumper land on the incline?
a) 4.15 s
We start by noticing that:
- The horizontal motion of the skier is a uniform motion, with constant velocity
and the distance covered along the horizontal direction in a time t is
- The vertical motion of the skier is a uniformly accelerated motion, with initial velocity 
and constant acceleration 
(where we take the downward direction as positive direction). Therefore, the vertical distance covered in a time t is
The time t at which the skier lands is the time at which the skier reaches the incline, whose slope is
below the horizontal
This happens when:
Substituting and solving for t, we find:
b) 143.6 m
Here we want to find the distance covered along the slope of the incline, so we need to find the horizontal and vertical components of the displacement first:
The distance covered along the slope is just the magnitude of the resultant displacement, so we can use Pythagorean's theorem:
