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o-na [289]
3 years ago
9

How much Ca(NO3)2 should be weighed out to have 0.650 mol?A) 66.4 g.B) 97.68.C) 107 g.D) 133 g.E) 165 g.

Chemistry
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

C) 107 g

Explanation:

Step 1: Calculate the molar mass of Ca(NO₃)₂

We can calculate the molar mass of Ca(NO₃)₂ by adding the masses of its elements.

M = 1 × Ca + 2 × N + 2 × 3 × O

M = 1 × 40.08 g/mol + 2 × 14.01 g/mol + 6 × 16.00 g/mol

M = 164.10 g/mol

Step 2: Calculate the mass corresponding to 0.650 moles of Ca(NO₃)₂

We multiply the number of moles by the molar mass.

0.650 mol × 164.10 g/mol = 107 g

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