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VMariaS [17]
3 years ago
8

Which is a nonmetal that becomes isoelectronic with argon when it forms its most common ion?

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
6 0

Answer:sulfur

Explanation:

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Suppose in an experiment to determine the amount of sodium hypochlorite in bleach, 0.0000524 mol K I O 3 were titrated with an u
11111nata11111 [884]

<u>Answer:</u> The amount of sodium thiosulfate required is 2.62\times 10^{-5} moles

<u>Explanation:</u>

Moles of KIO_3 solution given = 0.0000524 moles

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.0000524 moles of potassium iodate will react with = \frac{1}{2}\times 0.0000524=0.0000262mol of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is 2.62\times 10^{-5} moles

4 0
3 years ago
In two or more complete sentences explain how to balance the chemical equation, KClO3 ⟶ KCl + O2 and include all steps. Write yo
Serggg [28]

Answer:

2KClO3 -------> 2KCl + 3O2

Explanation:

First, in balancing a chemical reaction such as the one given in the question, you should understand that for an equation to be balanced, the number of atoms and ions on both sides of the equation that is the right and left side must be equal. This follows the law of conservation of mass which tells us that matter can neither be created nor destroyed but can be changed into another form.

Next is to begin balancing the equation by identifying and writing down the substances given:

KCl03 ---------> KCl + O2

Next is to count he number of the individual atoms on each side and find out if they are the same on both sides and if not you must follow the next step.

Add a corresponding number and use it to multiply the atoms involved

KClO3 ---------> KCl + O2

Oxygen is 3 on the left side and two on the other side, so we multiply the left hand side by 2 and the right hand side by 3

2KClO3 -----> KCl + 3O2

The potassium and Chlorine are no longer balanced, so you multiply the right had=nd side of KCl by 2.

2KClO3 -----> 2KCl + 3O2

The reactionis herefore balanced as both sides have equal number of atoms and ions.

5 0
4 years ago
Plssss help. 20 points!!!!!!!!!. Use periodic trends on the periodic table to predict the following.
krok68 [10]

Answer:

i. Atomic radius of an atom is defined as the total distance from the nucleus to the outermost shell of the atom.

On moving from left to right  ( Mg, K) in a period, more and more electrons get added up in the same shell and the attraction between the last electron and nucleus increases, which results in the shrinkage of size of an atom. Thus, decreasing the atomic radii of the atom on moving towards right of the periodic table.

As moving from top to bottom, there is an addition of shell around the nucleus and the outermost shell gets far away from the nucleus and hence, the distance between the nucleus and outermost shell increases.

Thus the order of atomic radii is : Ca > Mg > K

ii. The energy required to remove the last valence electron from isolated gaseous atom (first ionization energy) increases as we move from left to right in a period. It decreases on moving from top to bottom.

Thus the order of first ionization energy is : K > Mg > Ca

iii. The chemical properties depend on the valence elctrons and as the elements Mg and Ca both have two valence electrons , they have same chemical properties.

4 0
3 years ago
Scientist A produces 83.67 g KMnO4 while Scientist B produces 81.35 g KMnO4.
noname [10]

Answer:

Y_A=92.1\%\\\\Y_B=89.6\%

Explanation:

Hello there!

In this case, according to the given chemical equation for the reaction for the production of potassium permanganate, we can see a 2:2 mole ratio of this product to the starting manganese (II) oxide, which means, we can calculate the theoretical yield of the former via stoichiometry:

m_{KMnO_4}=50.0gMnO_2*\frac{1molMnO_2}{86.94gMnO_2}*\frac{2molKMnO_4}{2molMnO_2}  *\frac{158.034gKMnO_4}{1molKMnO_4} \\\\m_{KMnO_4}=90.9gKMnO_4

Now, we are able to compute the percent yields, by using the actual yield each scientist got:

Y_A=\frac{83.67g}{90.9g} *100\%=92.1\%\\\\Y_B=\frac{81.35g}{90.9g} *100\%=89.6\%

Regards!

8 0
3 years ago
Please guys help me with this​
Finger [1]

Answer:

It's B.

Explanation:

5 0
4 years ago
Read 2 more answers
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