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Alik [6]
1 year ago
9

Determine the charge on the unknown ion, X, in the compound Nax.

Chemistry
1 answer:
Leviafan [203]1 year ago
3 0

Answer:

wax i think

Explanation:

i don't understand a thing you just wrote

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I have a mass of 30 grams and a volume of 60 cm3 what is the density
Nesterboy [21]
I think it's 534 grams per cubic centimetre
7 0
2 years ago
What was the average speed of the truck for this trip?
Goshia [24]

Answer:

31.67 mph

Explanation:

To calculate the average speed of the truck, we must first obtain the total distance travelled by the truck followed by the total time taken for the truck to cover the distance travelled.

The following data were obtained from the question include:

Total distance) = 30 + 45 + 50 + 65 = 190 miles

Total time = 1 + 2 +1 +2 = 6 hours

Average speed =.?

Average speed = Total distance / Total time

Average speed = 190 /6

Average speed = 31.67 mph

Therefore, the average speed of the truck is 31.67 mph

8 0
3 years ago
Which of the following is not an example of a molecule?
9966 [12]
D. F

Molecules are a group of bonded atoms but Fluorine stands on its own
4 0
3 years ago
Read 2 more answers
How many molecules are in 4.62 moles of nitric acid (HNO3)?
Lena [83]

Answer:

2.8x10^24

Explanation:

To convert moles to molecules, multiply the number of moles by Avagadro's number (6.02x10^23. Round if required.

4.62mol × 6.02x10^23 = 2.8x10^24

6 0
3 years ago
For double-helix formation, DG can be measured to be 2 54 kJ mol 1 ( 2 13 kcal mol 1 ) at pH 7.0 in 1 M NaCl at 25 8C (298 K). T
levacccp [35]

Answer:

ΔS = -661.0J/mol is the entropy change for the system

ΔS = -842J/mol.K is the entropy change for the surroundings

Explanation:

From the relationship between ΔG, T, ΔH and ΔS,

Mathematically, ΔG = ΔH - TΔS

TΔS = ΔH - ΔS

ΔS = ΔH - ΔS / T

but ΔG = -54 kJ/mol, ΔH = -251 kJ/mol and T = 25 °C (298 K)

plugging into the equation,

ΔS = -251 kJ/mol - ( -54 kJ/mol) / 298

ΔS  = -0.6610KJ/mol or in J.mol

ΔS = -661.0J/mol is the entropy change for the system

  • For entropy change for the surroundings = ΔS = ΔH/T
  • ΔS  = -251 kJ/mol / 298K
  • ΔS = -0.84KJ/mol.K or -842J/mol.K is the entropy change for the surroundings
8 0
2 years ago
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