Who can help me for this question plz:(
1 answer:
You might be interested in
Answer:
a) 72mJ
b) 0.33m/s
c) 54mJ
d) 18mJ
Explanation:
(a) The total energy of the system is given by:
where k is the force constant and A is the amplitude. By replacing we get:
= 72mJ
(b) we can get the speed by the conservation of energy (the kinetic energy and potential energy must equal the total energy in any place):
where we have used that x=1.15cm=0.0115m; A=6.00cm=0.06m
(c) Again, by the conservation of energy:
(d)
hope this helps!!
Answer:
The radius of the moon's orbit, R = 7.715 x 10⁷ m
The orbital period of the moon, T = 14.48 hr
Explanation:
Given,
The orbital speed of the moon, v = 9.3 x 10³ m/s
The mass of Neptune, M = 1.0 x 10²⁶ Kg
The orbital velocity of the moon is given by the relation
m/s
Where,
r + h = R → radius of the moon's orbit
Therefore squaring the above equation and solving for r +h. The equation becomes
r + h = GM / v²
Substituting the given values in the above equation
R = (6.673 x 10⁻¹¹ x 1.0 x 10²⁶) / (9.3 x 10³)²
= 7.715 x 10⁷ m
The radius of the moon's orbit, R = 7.715 x 10⁷ m
The orbital period of the moon is given by the relation
T = 2π/ω
= 2πR/v ∵ ω = v/r
Substituting the values in the above equation
T = (2 x π x 7.715 x 10⁷ )/ 9.3 x 10³
= 52125.72969 s
= 14.48 hr
The orbital period of the moon, T = 14.48 hr