In order to compute the final velocity of the trains, we may apply the principle of conservation of momentum which is:
initial momentum = final momentum
m₁v₁ = m₂v₂
The final mass of the trains will be:
10,000 + 10,000 = 20,000 kg
Substituting the values into the equation:
10,000 * 3 = 20,000 * v
v = 1.5 m/s
The final velocity of the trains will be 1.5 m/s
Gravity bulb of hydrometer is made heavier so that its centre of gravity remains very low, when it is floating in denser liquids.
Initial angular velocity = 0 (starting from rest)
Final angular velocity = 30 rad/s
Distance traveled = (20 rev)*(2π rad/rev) = 40π rad
Let the angular acceleration be α rad/s².
Then
(30 rad/s)² = (0 rad/s)² + 2*(α rad/s²)*(40π rad)
α = 3.58 rad/s²
Answer: 3.58 rad/s² (nearest hundredth)
Answer:
V = - 2[m/s]
Explanation:
This is a classic problem of relative velocities, in order to solve it we must understand each of the velocities, given in the initial data of the problem.
VA = velocity of passenger A, = 1.5[km/h], it is the same velocity of the sidewalk
VB = 2 + 1.5 = 3.5 [km/h], that is the velocity observed by a person outside from the sidewalk.
And from the perspective of passenger B the speed of passanger A is:
VA-VB = - 2 [m/s]
It means that the passenger B is seen how passenger A is getting close to him and then passed.
Answer:
B. Design tests to measure and compare the energy released by
earthquakes
