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VLD [36.1K]
3 years ago
6

5. Sandor fills a bucket with water and whirls it in a vertical circle to demonstrate that the

Physics
1 answer:
just olya [345]3 years ago
3 0

Given that,

radius = 1.24 m

According to question,

The rope cannot push outwards. It must always have some slight tension or the bucket will fall.

We need to calculate the tension in the rope

At the top the force of gravity is

F=mg

The force needed to move the bucket in a circle is centripetal force.

So, if mg is ever greater than centripetal force then the bucket and the contents will start to fall.

The rope have a tension of less than zero.

We need to calculate the velocity of swing bucket

Using centripetal force

F=\dfrac{mv^2}{r}

mg=\dfrac{mv^2}{r}

g=\dfrac{v^2}{r}

v^2=gr

v=\sqrt{gr}

Put the value into the formula

v=\sqrt{9.8\times1.24}

v=3.49\ m/s

Hence, The minimum tension in the rope is less than zero .

The bucket swings with the velocity of 3.49 m/s.

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If a gas has a gage pressure of 156 kPa, it is absolute pressure is approximately
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Heat flows into a gas in a piston and work is performed on the gas by its surroundings. The amount of work done is equal to the
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The Internal energy of the gas did not change

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4 0
3 years ago
Use the equation for magnetic force on a moving charge to derive the equation for magnetic force on a current carrying wire. Sho
max2010maxim [7]

Answer:

The formula comes from Lorentz force law which includes both the electric and magnetic field. If the electric field is zero, the force law for just the magnetic field is <u>F=q(ν×B</u>) . Here, F  is force and is a vector because the force acts in a direction.  q  is the charge of the particle.  v  is velocity and is a vector because the particle is moving in some direction.  B is the magnetic flux density.

We can derive an expression for the magnetic force on a current by taking a sum of the magnetic forces on individual charges. (The forces add because they are in the same direction.) The force on an individual charge moving at the drift velocity vd.  Since the magnitude of B is constant at every line element of the loop (circle) and it dot product with the line element is B dl everywhere, therefore

                                                  ∮B dl=μ0 I

                                                  B ∮dl=μ0 I

                                                  B 2πr=μ0 I

                                                   B=μ02πr Id=μ0/4π I dl×rr3

Since, r can be written as r=(rcosθ,rsinθ,z) and dl as dl=(dl,0,0) And now, if we take the cross product we would get

                                               dl×r=−z dlj^+rsinθk^

and therefore the magnitude of dB is equal to

dB=μ0/4π I |dl×r|/r3=μ0/4π I z2+r2sin2θ−−−−−−−−−−√dl/r3

Thus, magnetic field is depending on r,θ,z.

Learn more about Force here-

brainly.com/question/2855467

#SPJ4

7 0
2 years ago
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