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lesantik [10]
3 years ago
8

2,3-Dimethylbutane reacts with bromine in the presence of light to give a monobrominated product. Further reaction gives a good

yield of a dibrominated product. Predict the structures of these products, and propose a mechanism for the formation of the monobrominated product.

Chemistry
1 answer:
irga5000 [103]3 years ago
3 0

Answer:

Explanation:

find the solution below

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Write a complete, balanced chemical equation where tin metal reacts with aqueous hydrochloric acid to produce tin(II) chloride a
Naily [24]

Answer:

Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g)

Explanation:

The net reaction is Z n ( s ) + 2 H + ( a q ) → Z n 2 + ( a q ) + H 2 ( g ) The C l − ions are spectators - they don't change.

7 0
2 years ago
In the reaction 2H2O (l) + 2Cl– (aq) → H2 (g) + Cl2 (g) + 2OH– (aq), which substance is oxidized?
pashok25 [27]

F. None of the above [Cl^(-) is oxidized]

<em>No Cl atoms are available</em> to be oxidized, only Cl^(-)ions

2Cl^(-) → Cl_2 + 2e^(-)

The substance that <em>loses electrons</em> is oxidized.

Remember <em>OIL</em> RIG (<em>O</em>xidation<em> I</em>s <em>L</em>oss of electrons) and

<em>LEO</em> the lion says GER (<em>L</em>oss of Electrons is <em>O</em>xidation).

3 0
3 years ago
if 1.386 g of mg ribbon combusts to form 2.309 g of oxide product, calculate the experimental mass percent of oxygen from this d
Pavlova-9 [17]

1.386 g of Mg ribbon combusts to form 2.309 g of oxide product. The mass percent of oxygen in the oxide is 40.0 %.

Let's consider the reaction for the combustion of Mg.

Mg + 1/2 O₂ ⇒ MgO

1.386 g of Mg combusts to form 2.309 g of MgO. We want to determine the mass of oxygen in MgO. According to Lavoisier's law of conservation of mass, matter is not created nor destroyed over the course of a chemical reaction. Then, the mass of Mg in the reactants is equal to the mass of Mg in MgO. The mass of the magnesium oxide is the sum of the masses of magnesium and oxygen. The <u>mass of oxygen in the oxide</u> is:

mMgO = mMg + mO\\mO = mMgO - mMg = 2.309 g - 1.386 g = 0.923 g

We can calculate the mass percent of O in MgO using the following expression.

\% O = \frac{mO}{mMgO} \times 100\% = \frac{0.923 g}{2.309g} \times 100\%  = 40.0 \%

You can learn more about mass percent here: brainly.com/question/14990953

3 0
1 year ago
What was the control in Pasteur's experiment?
Sholpan [36]

Answer:

a straight neck flask to allow air to get in

Explanation:

I took the test eWe

8 0
3 years ago
at what height is an object that has a mass of 16kg, if it’s gravitational potential energy is 7500J?
dolphi86 [110]

Answer:

46.875

Explanation:

P.E=MGH

7500=16*10*h

7500=160h

h=7500/160

h=46.875

5 0
2 years ago
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