Answer:
Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g)
Explanation:
The net reaction is Z n ( s ) + 2 H + ( a q ) → Z n 2 + ( a q ) + H 2 ( g ) The C l − ions are spectators - they don't change.
F. None of the above [Cl^(-) is oxidized]
<em>No Cl atoms are available</em> to be oxidized, only Cl^(-)ions
2Cl^(-) → Cl_2 + 2e^(-)
The substance that <em>loses electrons</em> is oxidized.
Remember <em>OIL</em> RIG (<em>O</em>xidation<em> I</em>s <em>L</em>oss of electrons) and
<em>LEO</em> the lion says GER (<em>L</em>oss of Electrons is <em>O</em>xidation).
1.386 g of Mg ribbon combusts to form 2.309 g of oxide product. The mass percent of oxygen in the oxide is 40.0 %.
Let's consider the reaction for the combustion of Mg.
Mg + 1/2 O₂ ⇒ MgO
1.386 g of Mg combusts to form 2.309 g of MgO. We want to determine the mass of oxygen in MgO. According to Lavoisier's law of conservation of mass, matter is not created nor destroyed over the course of a chemical reaction. Then, the mass of Mg in the reactants is equal to the mass of Mg in MgO. The mass of the magnesium oxide is the sum of the masses of magnesium and oxygen. The <u>mass of oxygen in the oxide</u> is:

We can calculate the mass percent of O in MgO using the following expression.

You can learn more about mass percent here: brainly.com/question/14990953
Answer:
a straight neck flask to allow air to get in
Explanation:
I took the test eWe