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IgorC [24]
4 years ago
5

The velocity of the transverse waves produced by an earthquake is 4.05 km/s, while that of the longitudinal waves is 7.695 km/s.

A seismograph records the arrival of the transverse waves 69.9 s after that of the longitudinal waves. How far away was the earthquake? Answer in units of km.
Physics
1 answer:
lora16 [44]4 years ago
4 0

Answer:

x = 600 Km

Explanation:

given,

speed of transverse wave = 4.05 Km/s

speed of longitudinal wave = 7.695 Km/s

difference of the time of arrival of wave = 69.9 s

now,

t₂ - t₁ = 69.9 s

let x be the distance

\dfrac{x}{4.05} - \dfrac{x}{7.695} = 69.9

x = \dfrac{69.9\times 4.05 \times 7.695}{7.695-4.05}

x = 597.645 Km

x = 600 Km

distance of recorder from the site is 600 Km approximately.

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Answer:

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4 years ago
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Statement A: Area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.
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Explanation:

Formula for calculating the area of a  rectangle A = Length *width

For statement A;

Given area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.

Area of the rectangle = 2.536mm * 1.4mm

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The rule of significant figures states that we should always convert the answer to the least number of significant figure amount the given value in question. Since 1.4mm has 2 significant figure, hence we will convert our answer to 2 significant figure.

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Area of the rectangle = 2.536mm * 1.41mm

Area of the rectangle = 3.57576mm²

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Area of the rectangle = 3.58mm² (to 3sf)

Based on the conversion, it can be seen that 3.6mm²  is greater than 3.58mm², hence the area of rectangle in statement A is greater than the area of the rectangle in statement B.

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Two neutral objects will not have any electric force of attraction or repulsion between them.

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