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Luda [366]
4 years ago
11

How does the force due to gravity on Mars compare to the force due to gravity on Earth? , and Using Newton's Second Law, explain

how a rocket can have an increase in acceleration over time.
Physics
1 answer:
navik [9.2K]4 years ago
4 0
As accurately described by Einstein's theory of relativity, gravity is not necessarily a force, but a consequence of the curvature of space time that is caused by the uneven distribution of mass. But this could also be approximated by Newton's Law of Universal Motion. Gravity is a force acting upon two objects with masses at a certain amount of distance. So, the greater the mass, and the closer the objects are, the greater is the force of gravity. So, if you compare the gravity on Mars compared to Earth at a given distance, compare their masses. The mass of Earth is 5.972 × 10^24 kg while that of Mars is <span>6.39 × 10^23 kg. So, the gravity on Earth is much greater because Earth is heavier.

For the second question, let's base on Newton's Second Law of Motion which states: the force exerted on or by the object, is equal to its mass times acceleration. In equation, F = ma. So, if you want to increase acceleration, the force should be greater, while the mass should be lighter.</span>
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. A 2.0-m wire carries a current of 15 A directed along the positive x axis in a region where the magnetic field is uniform and
Lady bird [3.3K]

Answer:

The resulting magnetic force on the wire is -1.2kN

Explanation:

The magnetic force on a current carrying wire of length 'L' with current 'I' in a magnetic field B is

F = I (L*B)

Finding (L * B) , where L = (2, 0, 0)m , B = (30, -40, 0)

L x B = \left[\begin{array}{ccc}i&j&k\\2&0&0\\30&-40&0\end{array}\right] = (0, 0, -80)

we can now solve

F = I (L x B) = I (-80)

F = -1200 kmN

F = -1200 kN * 10⁻³

F = -1.2kN

6 0
3 years ago
What is the difference between transverse waves and longitudinal waves?
Degger [83]

D.transverse waves move perpendicular and longitudinal waves move parallel to the direction of energy movement..

3 0
3 years ago
Read 2 more answers
When a man travel from hilly to terai what will happen to weight and why?
juin [17]

Answer:

When a man travels from Hilly region to Terai region, his weight gradually increases because the value of g is more at the Terai region than that in hilly region. 3. An object weights 20 N in air and 16 N in liquid, then answer the following questions.

Explanation:

because the value of g is more at the Terai region than that in hilly region. 3. An object weights 20 N in air and 16 N in liquid, then answer the following questions.

6 0
3 years ago
How might you describe the mathematical procedure of finding the displacement when an object travels in two opposite directions?
levacccp [35]
Displacement is a vector quantity. So, you incorporate the vector calculations when you try to determine the resultant vector. This is the shortest path from the starting point to the endpoint. If they are moving on one axis only, you use sign conventions. For motions moving to the left, use the negative sign. If it's moving to the right, then use the positive sign. Now, it the object moves 2 km to the left, and 2 km also to the right, the displacement is zero.

Displacement = 2 km - 2km = 0

Generally, the equation is:
<span>Displacement = Distance of motion to the right - Distance of motion to the left</span>
4 0
3 years ago
A hydrogen atom in a galaxy moving with a speed of 6.65×106 m/???? away from the Earth emits light with a wavelength of 5.13×10−
Mumz [18]

Answer:

The observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m.

Explanation:

Given that,

The actual wavelength of the hydrogen atom, \lambda_a=5.13\times 10^{-7}\ m

A hydrogen atom in a galaxy moving with a speed of, v=6.65\times 10^6\ m/s

We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

v=c\times \dfrac{\lambda_o-\lambda_a}{\lambda_a}

\lambda_o is the observed wavelength

\lambda_o=\dfrac{v\lambda_a}{c}+\lambda_a\\\\\lambda_o=\dfrac{6.65\times 10^6\times 5.13\times 10^{-7}}{3\times 10^8}+5.13\times 10^{-7}\\\\\lambda_o=5.24\times 10^{-7}\ m

So, the observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m. Hence, this is the required solution.

8 0
3 years ago
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