Answer:
Specific gravity for liquids is nearly always measured with respect to water at its densest
Explanation:
I believe this question ask for the energy dissipated by
friction.
The overall energy equation for this is:
F = PE – KE
where F is friction loss, PE is potential energy = m g h,
KE is kinetic energy = 0.5 m v^2
<span>F = 66 kg * 9.8 m/s^2 * 170 m – 0.5 * 66 kg * (11 m/s)^2</span>
<span>F = 105,963 J ~ 106,000 J </span>
The time of fall for the two balloons is equal.
Here the conditions given resembles a free fall. Since the air resistance is negligible, gravitational force is the only force acting on both the balloons which means the two balloons are falling in a vacuum. In a vacuum, if two objects of different mass are thrown from the same height, both objects will reach the ground at the same time.
Free fall is nothing but a condition in which an object falls solely under the influence of gravity.
Therefore, the time of fall for both yellow and red water balloons is equal no matter the weight where air resistance is negligible.
To know more about free fall
brainly.com/question/13299152
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