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kondor19780726 [428]

3 years ago

11

At what minimum speed must a roller coaster be traveling when upside down at the top of a circle so that the passengers do not f

all out? Assume a radius of curvature of 6.9 m

1 answer:

Basile [38]3 years ago

7 0

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Atomic math challenge will give brainly and thanks

nevsk [136]

Answer:

1. Hydrogen

Atomic # = 1

Atomic Mass = 1.00794 ( If you round it it's 1.008 )

# of protons = 1

# of neutrons = none

# of electrons = 1

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2 years ago

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The Burj Khalifa in Dubai is the world's tallest building. The structure is 828 m (2716.5 ft) and has more than 160 stories. A t

lakkis [162]

Explanation:

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2 years ago

If the speedometer of your car reads a constant speedometer of your car reads a constant speed of 40km/hr , can you say the car

Harrizon [31]

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3 years ago

Someone please help! It is a few science questions. Fairly easy!

borishaifa [10]

1) $0.92 * 100 = 92$ <Solve using the formula which is:
Mass=Density×Volume
$M=D*V$

2) $3.98 ml$

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$5*2*4=40$
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3 years ago

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A rod extending between x = 0 and x = 13.0 cm has uniform cross-sectional area A = 8.00 cm2. Its density increases steadily betw

mezya [45]

Answer:

The mass is $m = 3.45408 kg$

Explanation:

From the question we are told that

The extension of the rod is $from , \ x_1 = 0 \to x_2 = 13.0$

The area is $A = 8.0 cm^2$

The density increase as follows $from \ \rho_1 =2.5 g/cm^2 \to \rho_2= 19.0 g/cm^3$

The equation $\rho = B + Cx$

at $x_1= 0$ $\rho_1 =2.5 g/cm^2$

So

$2.5 = B + 0$

=> $B =2.5$

So at $x_2 = 13.0$ , $\rho_2= 19.0 g/cm^3$

So

$19.0 = 2.5 + C(13)$

=> $C = 1.27$

Now

$m = 8 \int\limits^{13}_{0} {2.5 + 1.27x} \, dx$

$m = 8 [{2.5 +\frac{ 1.27x^2}{2} } ]\left | 13} \atop {0}} \right.$

$m = 8 [{2.5 +\frac{ 1.27(13)^2}{2} } ]$

$m = 3454.08 g$

$m = 3.45408 kg$

8 0

2 years ago