Friction, lack/loss of kinetic energy
Power = (voltage) x (current)
Divide each side by 'voltage': Current = power / voltage
= (60 watts) / (120 volts) = 0.5 ampere
Answer:
-D) Identify a question, make observations, create a hypothesis, and then set up an experiment to test the hypothesis because need to follow the steps to do the experiment properly.
Answer:
the energy when it reaches the ground is equal to the energy when the spring is compressed.
Explanation:
For this comparison let's use the conservation of energy theorem.
Starting point. Compressed spring
Em₀ = K_e = ½ k x²
Final point. When the box hits the ground
Em_f = K = ½ m v²
since friction is zero, energy is conserved
Em₀ = Em_f
1 / 2k x² = ½ m v²
v = x
Therefore, the energy when it reaches the ground is equal to the energy when the spring is compressed.
11. Density of the piece of wood = 3000 g/cm³
12. Density of wooden block = 2 g/cm³. and it will not float in water.
13. Volume of the plastic ball should be 250 mL
14. Mass of the ice cube = 0.162 g
15. Volume of gasoline spilled is equal to 2000 mL
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11.
<u>Formula:</u>
Given:
Mass of wood piece = 7500 g
Volume of wood piece = 2.5 cm³
Therefore,
Density of the piece of wood = 3000 g/cm³
12.
<u>Formula:</u>
Given:
Dimensions of wooden block = length × width × height = 5 cm × 4 cm × 2 cm
Mass = 80.0 g
Volume of wooden block =
Therefore,
Density of wooden block = 2 g/cm³.
Density of water is equal to 1 g/cm³
2 g/cm³ > 1 g/cm³
Since density of wooden block is greater than the density of water, the piece of wood will not float in water. It will sink.
13.
<u>Formula:</u>
Given:
Mass of the ball = 125 g
Density = 0.5 g/mL
Therefore,
Volume = 250 mL
Volume of the plastic ball should be 250 mL
14.
<u>Formula:</u>
Given:
Dimensions of ice cube = length × width × height = 3 cm × 3 cm × 3 cm
Density = 0.006 g/mL
Volume of ice cube =
Since,
Therefore,
Mass of the ice cube = 0.162 g.
15.
<u>Formula:</u>
Given:
Mass of gasoline = 1330 g
Density = 0.665 g/mL
Therefore,
Volume = 2000 mL
Volume of gasoline spilled is equal to 2000 mL