I am quite sure the first one is Friction, but I am not sure about the second one. Is it wind?
Answer:
12.0 meters
Explanation:
Given:
v₀ = 0 m/s
a₁ = 0.281 m/s²
t₁ = 5.44 s
a₂ = 1.43 m/s²
t₂ = 2.42 s
Find: x
First, find the velocity reached at the end of the first acceleration.
v = at + v₀
v = (0.281 m/s²) (5.44 s) + 0 m/s
v = 1.53 m/s
Next, find the position reached at the end of the first acceleration.
x = x₀ + v₀ t + ½ at²
x = 0 m + (0 m/s) (5.44 s) + ½ (0.281 m/s²) (5.44 s)²
x = 4.16 m
Finally, find the position reached at the end of the second acceleration.
x = x₀ + v₀ t + ½ at²
x = 4.16 m + (1.53 m/s) (2.42 s) + ½ (1.43 m/s²) (2.42 s)²
x = 12.0 m
Answer:
The resistance of the inductor at resonance is 258.76 ohms.
Explanation:
Given;
resistance of the resistor, R = 305 ohm
capacitance of the capacitor, C = 1.1 μF = 1.1 x 10⁻⁶ F
inductance of the inductor, L = 42 mH = 42 x 10⁻³ H = 0.042 H
At resonance the inductive reactance is equal to capacitive reactance.
Where;
F₀ is the resonance frequency
The inductive reactance is given by;
Therefore, the resistance of the inductor at resonance is 258.76 ohms.
The boiling point of water, or any liquid, varies according to the surrounding atmospheric pressure. A liquid boils, or begins turning to vapor, when its internal vapor pressure equals the atmospheric pressure.
Answer:
The correct answer is - 200000 J
Explanation:
We use the formula of kinetic energy:
The formula to calculate kinetic energy is,
Here,
Ec =1/2 x m x v^2
The mass of the roller coaster is, m = 1000 k
g
The speed of the roller coaster is, v = 20.0 m/s
Therefore,
Ec=1/2 x 1000kg x (20m/s)^2 = 200.000Joule
200,000J
