Syrup, molasses, and honey have a lower viscosity than water
Answer:
Explanation:
Hello,
At first, it is convenient to compute Kp, since it remains constant during the proposed situation:
Now, since the volume is halved, the pressures of N₂O₄ and NO₂ are doubled, 1.00 atm and 0.538 atm respectively, but now they are considered as the initial pressures, so a change is now present in order to take the reaction again to the equilibrium. Besides, the reaction changes as the products have more moles as:
Thus, the law of mass action goes (considering the reverse reaction):
Hence, solving for by using solver or the quadratic equation, one obtains:
Nonetheless, the feasible solution is 0.072 atm as 0.50 atm leads to a negative pressure of NO₂, thus, the new equilibrium pressures are:
Best regards.
I dont know if im right but i belive its c
They subtract the atomic number from the atomic mass.
Hi! I hope this helps, here’s the answer.
<span>2NH3 + 3/2O2 --> N2 +
3H2O </span><span>
<span>NH3 + 3/4O2 --> 1/2N2 + 3/2H2O </span></span>
<span>Here, the sign of deltaS^0 is one molecule (^0) thus, the
coefficient of NH3 should be ONE.</span>