Answer:
I believe the answer is

Explanation:
I may be incorrect because I used to do this a long time ago but I believe I am correct
HOPE THIS HELPS!
(:
Explanation:
Given that,
Object distance u= -110 cm
Image distance v= 55 cm
We need to calculate the focal length for diverging lens
Using formula of lens

Put the value into the formula


The focal length of the diverging lens is 36.6 cm.
Now given a thin lens with same magnitude of focal length 36.6 cm is replaced.
Here, The object distance is again the same.
We need to calculate the image distance for converging lens
Using formula of lens

Here, focal length is positive for converging lens



The distance of the image is 54.85 cm from converging lens.
Hence, This is the required solution.
Answer:
Your answer would be C <u><em>Hope this helps</em></u>
Answer:
The planes’ acceleration from A to B is 500m/s^2
Explanation:
Given that the initial velocity u is 8000m/s
and also given the final velocity v=10,000 m/s
the time taken to move from A to B = 40 second
The acceleration is defined as the rate of change of velocity with time
we know that the expression for acceleration is given as
a=(v-u)/t
substituting our given data into the expression for a we have
a=(10000-8000)/40
a=2000/40
a=500m/s^2
The planes’ acceleration from A to B is 500m/s^2
solution:
We know v0 = 0, a = 9.8, t = 4.0. We need to solve for v
so,
we use the equation:
v = v0 + at
v = 0 + 9.8*4.0
v = 39.2 m/s
Now we just need to solve for d, so we use the equation:
d = v0t + 1/2*a*t^2
d = 0*4.0 + 1/2*9.8*4.0^2
d = 78.4 m