Answer:
This formula R =ρL/A
Where R = resistance of wire, ρ = resistivity of the wire and A = area of the wire. Shows there is an inverse relationship between Resistance and Area of the wire.
Explanation:
A simple way to explain the physics behind such an electrical code is to compare the flow of current through wires to the flow of water through pipes, they are similar in any respect. The resistance to the flow of current in an electric circuit is similar to the frictional experienced by water when flowing through water pipes. Just as water will flow easily with little resistance through a water pipe with the larger cross-sectional area than one with a smaller cross-sectional area, in the same way, wires with larger cross-sectional area will allow the flow of larger amount of current compared to wires with smaller cross-sectional area assuming all other variables are the same.
From the formula R =ρL/A
Where R = resistance of wire, ρ = resistivity of the wire and A = area of the wire
We can see that the resistance and area of the wire have an inverse relationship. An increase in the area of the wire will lead to a decrease in the resistance of the wire.
Answer:
Explanation:
https://web.lemoyne.edu/courseinformation/mth%20112/rinaman/instman/SOLUTION.PDF
Answer:
Approximately
.
Explanation:
It is given that
and
are connected in a circuit in parallel.
Assume that this circuit is powered with a direct current power supply of voltage
.
Since
and
are connected in parallel, the voltage across the two resistors would both be
. Thus, the current going through the two resistors would be
and
, respectively.
Also because the two resistors are connected in parallel, the total current in this circuit would be the sum of the current in each resistor:
.
In other words, if the voltage across this circuit is
, the total current in this circuit would be
. The (equivalent) resistance
of this circuit would be:
.
Given that
and
:
.
An inner transition metal (ITM) is one of a group of chemical elements on the periodic table. They are normally shown in two rows below all the other elements. They include elements 57-71 (lanthanides) and 89-103 (actinides).
Answer:
The gauge pressure is 
Explanation:
From the question we are told that
The height of the water contained is 
The height of liquid in the cylinder is 
At the bottom of the cylinder the gauge pressure is mathematically represented as

Where
is the pressure of water which is mathematically represented as

Now
is the density of water with a constant values of 
substituting values


While
is the pressure of oil which is mathematically represented as

Where
is the density of oil with a constant value

substituting values


Therefore

