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IRINA_888 [86]
3 years ago
12

4. A student is doing experiments with CO2(q) . Originally a sample of the gas is in a rigid container at 299 Kand 0.70 atm. The

student increases the temperature of the CO2(g) ) in the container to 425 K the CO2(g)mo molecul (b) Calculate the pressure of the CO - (g) ) in the container at 425 K (C) In terms of kinetic molecular theory, briefly explain why the pressure of the CO2(g) in the container changes as it is heated to 425 K. (d) The student measures the actual pressure of the CO2(g) in the container at 425 K and observes that it is less than the pressure predicted by the ideal gas law . Explain this observation ,
Chemistry
1 answer:
marta [7]3 years ago
8 0

Answer:

b. 0,99atm

c. Answer is in the explanation

d. Answer is in the explanation

Explanation:

b. Using Gay-Lussac's law:

P₁T₂ = P₂T₁

P₁: 0,70 atm; T₂: 425K; P₂: ??; T₁: 299K

0,70atm×425K / 299K = <em>0,99 atm</em>

c. Using kinetic molecular theory, the increasing of temperature increases the kinetic energy of gas particles and if kinetic energy increases, the pressure increases. That means the increasing of temperature increases the pressure in the system.

d. Now, the increases in kinetic energy of gases increase the collisions betwen particles. As these intermolecular forces that are not taken into account in ideal gas law, the observed pressure will be different to the pressure predicted by ideal gas law.

I hope it helps!

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pav-90 [236]
<h3>Answer:</h3>

388.94 g N₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Stoichiometry
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN]   4HCl (g) + 6NO (g) → 5N₂ (g) + 6H₂O (g)

[Given]   404.87 g HCl

<u>Step 2: Identify Conversions</u>

[RxN]   4 mol HCl = 5 mol N₂

Molar Mass of H - 1.01 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of HCl - 1.01 + 35.45 = 36.46 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of N₂ - 2(14.01) = 28.02 g/mol

<u>Step 3: Stoichiometry</u>

<u />404.87 \ g \ HCl(\frac{1 \ mol \ HCl}{36.46 \ g \ HCl} )(\frac{5 \ mol \ N_2}{4 \ mol \ HCl} )(\frac{28.02 \ g \ N_2}{1 \ mol \ N_2} ) = 388.935 g N₂

<u>Step 4: Check</u>

<em>We are given 5 sig figs. Follow sig fig rules and round.</em>

388.935 g N₂ ≈ 388.94 g N₂

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3 years ago
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