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Lyrx [107]
3 years ago
9

An electric current is flowing through a long cylindrical conductor with radius a. The current density J is uniform in the cylin

der. In this problem we consider an imaginary cylinder with radius r around the axis AB where r

Physics
1 answer:
RUDIKE [14]3 years ago
4 0

Answer:

Check the explanation

Explanation:

Kindly check the attached images below to see the step by step explanation to the question above.

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Read 2 more answers
A 795-loop square armature coil with a side of 10. 5 cm rotates at 70. 0 rev/s in a uniform magnetic field of strength 0. 45 t.
Agata [3.3K]

The rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

RMS is an acronym for root mean squared. An RMS value is more than just the "amount of AC power that causes the same heating impact as an analogous DC power" or something along those lines.

No. of loop = 795

Diameter of the coil = 10.5 cm

Radius of the coil = 5.25 cm

Magnetic Field, B = 0.45 T

Time, t = 70.0 rev/s

              V_{rms} =\frac{NwAB}{\sqrt{2} }

Where,

              N = No. of loop

              A = Area of the coil

              B = Magnetic Field

              V_{rms} = Voltage rms

Area of the coil = πr²

                        = 86.57 cm²

w = 2π/t

   =( 2 × 3.141)/70.0

   = 0.089

V_{rms} =\frac{795*0.089*86.57* 0.45}{\sqrt{2} }\\\\V_{rms} =\frac{2756.36}{\sqrt{2} }\\\\\\V_{rms} =\frac{2756.36}{1.414 }\\\\V_{rms} = 1.94 * 10^-^5 V

Therefore, the rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

Learn more about rms voltage here:

brainly.com/question/13156072

#SPJ4

8 0
1 year ago
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