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KonstantinChe [14]
3 years ago
5

Use this free body diagram to help you find the magnitude of the force needed to keep this block in static equilibrium.

Physics
1 answer:
Bingel [31]3 years ago
8 0

Split <em>F</em>₁ into its horizontal and vertical components:

<em>F</em>₁ = <em>F</em>₁ cos(<em>θ</em>) <em>i</em> + <em>F</em>₁ sin(<em>θ</em>) <em>j</em>

(boldface = vector; regular font = magnitude)

By Newton's second law, if the object is in equilibrium, then

• the net horizontal force on the block is

∑ <em>F</em> = <em>F</em>₁ cos(<em>θ</em>) - <em>F</em>₃ = 0   →   <em>F</em>₁ cos(<em>θ</em>) = 70 N

• the net vertical force is

∑ <em>F</em> = <em>F</em>₁ sin(<em>θ</em>) + <em>F</em>₂ - <em>W</em> = 0   →   <em>F</em>₁ sin(<em>θ</em>) = 65 N

Recall that cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1 for any <em>θ</em>, so we have

(<em>F</em>₁ cos(<em>θ</em>))² + (<em>F</em>₁ sin(<em>θ</em>))² = (70 N)² + (65 N)²

<em>F</em>₁² = 9125 N²

<em>F</em>₁ = √(9125 N²) ≈ 95.5 N

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