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satela [25.4K]
3 years ago
12

How would you calculated the distance travelled by the car using its velocity-time graph

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

Answer:

Measure the area under the graph.

Explanation:

To calculate the distance traveled by a car (or anything) using a velocity-time graph, just measure the area under the graph! This is super easy. :)

I will use the graph below as an example. If you needed to find the distance traveled from 4 seconds to 10 seconds, you would just find the area under those two points. The dark blue is the area we need to find the area of.

The area of a rectangle is a A = bh

A = bh

A = (6 s)(8 m/s)

A = 48 meters

If you wanted to find the area from 0 seconds to 4 seconds, you would find the area of the light blue triangle.

A = 1/2bh

A = 1/2(4 s)(8 m/s)

A = 16 meters

If you wanted to find the area from 0 seconds to 10 seconds, you would just add these two areas!

A1 + A2

48 meters + 16 meters = 64 meters

I really hope this helped! :)

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A speed skater moving across frictionless ice at 9.2 m/s hits a 5.0 m wide patch of rough ice. She slows steadily, then continue
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Answer:

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

Explanation:

The distance travelled on the rough ice is equal to the width of the rough ice.

distance d = 5.0 m

Initial speed u = 9.2 m/s

Final speed v = 5.8 m/s

The time taken to move through the rough ice can be calculated using the equation of motion;

d = 0.5(u+v)t

time t = 2d/(u+v)

Substituting the given values;

t = 2(5)/(9.2+5.8)

t = 2/3 = 0.66667 second

The acceleration is the change in velocity per unit time;

acceleration a = ∆v/t

a = (v-u)/t

Substituting the values;

a = (5.8-9.2)/0.66667

a = -5.099974500127

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

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Answer:

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Answer:

Explanation:

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