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satela [25.4K]
3 years ago
12

How would you calculated the distance travelled by the car using its velocity-time graph

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

Answer:

Measure the area under the graph.

Explanation:

To calculate the distance traveled by a car (or anything) using a velocity-time graph, just measure the area under the graph! This is super easy. :)

I will use the graph below as an example. If you needed to find the distance traveled from 4 seconds to 10 seconds, you would just find the area under those two points. The dark blue is the area we need to find the area of.

The area of a rectangle is a A = bh

A = bh

A = (6 s)(8 m/s)

A = 48 meters

If you wanted to find the area from 0 seconds to 4 seconds, you would find the area of the light blue triangle.

A = 1/2bh

A = 1/2(4 s)(8 m/s)

A = 16 meters

If you wanted to find the area from 0 seconds to 10 seconds, you would just add these two areas!

A1 + A2

48 meters + 16 meters = 64 meters

I really hope this helped! :)

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s = distance covered = 320 m

Vi = Initial Velocity = 0 m/s (Since, dragster starts from rest)

t = time taken = ?

a = acceleration of dragster = 10 m/s²

Therefore,

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agasfer [191]

Answer:

T_1=T_3=\dfrac{2\pi}{21}

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Explanation:

Wave 1, y_1=0.12\ cos(3x-21t)

Wave 2, y_2=0.15\ sin(6x+42t)

Wave 3, y_3=0.13\ cos(6x+21t)

Wave 4, y_4=-0.27\ sin(3x-42t)

The general equation of travelling wave is given by :

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The value of \omega will remain the same if we take phase difference into account.

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For second wave,

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T_2=\dfrac{2\pi}{42}

For the third wave,

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T_3=\dfrac{2\pi}{21}

For the fourth wave,

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3 0
3 years ago
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