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Ann [662]
4 years ago
14

A falling back in mid air has what

Physics
1 answer:
Umnica [9.8K]4 years ago
4 0
Acceleration I think if I’m not mistaken
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a pole vaulter at the top of his vault is 6.15 m in the air . if he has a gravitational potential energy of 4o42 j , what is his
Ksenya-84 [330]
<span>82.0 kg I am going to assume that there is a typo for the number of joules of energy. Doing a google search for this exact question showed this question multiple times with a value of 4942 joules which makes sense given how close the "o" key is to the "9" key. Because of this, I will assume that the correct value for the number of joules is 4942. With that in mind, here's the solution. The gravitational potential energy is expressed as the mass multiplied by the height, multiplied by the local gravitational acceleration. So: E = MHA Solving for M, the substituting the known values and calculating gives: E = MHA E/(HA) = M 4942/(6.15*9.8) = M 4942/60.27 = M 81.99767712 = M Rounding to 3 significant figures gives 82.0 kg</span>
4 0
4 years ago
Read 2 more answers
12. An example of an atom that has no charge is one that has A. 3 protons, 1 electron, and 3 neutrons. B. 3 protons, 2 electrons
andreyandreev [35.5K]
_____________________________

[D. 2 protons, 2 electrons, and 1 neutron.]

As we know that, protons are embedded in the nucleus with neutron having no charge. So, nucleus has positive charge. Electrons are revolved around the nucleus of the atom. Proton has positive charge and electron has negative charge.

Number of proton = Number of electron.

Hence, both 2 protons and 2 electrons make the atom electrically neutral. So, the net charge of atom is 0. Neutron are the subatomic particle which has only mass.

_____________________________
8 0
3 years ago
What are some sources of error in a refraction lab using pins and a glass block?
ser-zykov [4K]

DONT WORRY

ANSWER KO YAN NG MADALI

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6 0
2 years ago
Calculate the magnitude of the focal length and power of a spherical mirror that has a radius of 5.00 cm.
yarga [219]

Answer:

2.5 cm

40 D

Explanation:

When the radius of curvature of a lens is divided by 2 we get the focal length of the lens.

Focal length is given by

f=\dfrac{R}{2}\\\Rightarrow f=\dfrac{5}{2}\\\Rightarrow f=2.5\ cm

The focal length of the lens is 2.5 cm

When we divide 1 by the focal length in the unit of meters we get the power of a lens

Power of a lens is given by

P=\dfrac{1}{f}\\\Rightarrow P=\dfrac{1}{0.025}\\\Rightarrow P=40\ D

The power of the lens is 40 D

5 0
4 years ago
A mass weight of 120N is hung from two strings. what is the tension?
kramer
The weight should be shared between the two string equally. Therefore, tension in each string, T is;

T = 120 N/2 = 60 N
7 0
4 years ago
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