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Ann [662]
3 years ago
14

A falling back in mid air has what

Physics
1 answer:
Umnica [9.8K]3 years ago
4 0
Acceleration I think if I’m not mistaken
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A thin ring of charge of radius R lies in the x-y plane and is centered on the z-axis. The linear charge density, l, of the loop
Kruka [31]

Answer:

Linear charge density (I) = Q/2πR

Explanation:

Linear charge density (I) = charge (Q) per unit length(L)

I = Q/L

For a thin ring of charge with radius R, the length will be equal to the circumference of a circle.

Circumference of a circle = 2πR

Then, the length of the thin ring of charge is 2πR

Linear charge density (I) = Q/2πR

Therefore, for a thin ring of charge of radius R, which lies in the x-y plane and is centered on the z-axis. The linear charge density, l, of the loop is given by Q/2πR

7 0
3 years ago
Thinking about an analogue clock, calculate the angular displacement in revolutions, radians and degrees for the following: • A
Inessa [10]

Answer:

1.047 rad

Explanation:

A secondhand makes a complete revolution (360 degrees) in 60 seconds, so it displaces 6 degrees for every second of elapsed time (360/60 = 6).

And in 10 seconds, it will make a displacement of 10 degrees (6 * 10 = 60).

Finally converting the result into Radians by multiplication with π/180.

5 0
2 years ago
If Star A is twice as far as Star B, and they are identical in all other ways, then the
baherus [9]

Answer:1/4 the brightness of star b

Explanation:

8 0
3 years ago
A ball rolls off the edge of a table with a fairly large horizontal velocity. Which of the following statements are true? (Selec
Degger [83]

Answer:

A.The vertical velocity is constantly increasing as the ball falls.

B.The horizontal velocity does not noticeably change as the ball falls.

G.The horizontal velocity does not affect how long it will take the ball to fall to the floor.

H.The velocity vector of the ball changes as it travels through the air.

Explanation:

As the ball is projected horizontally so here the vertical component of the velocity is zero

So the time to reach the ground is given as

H = \frac{1}{2} gt^2

so we will have

t = \sqrt{\frac{2H}{g}}

so this is the same time as the ball is dropped from H height

Since there is no force in horizontal direction so its horizontal velocity will always remain constant while vertical velocity will change at constant rate which is equal to acceleration due to gravity.

So overall the velocity vector will change due to net acceleration g

4 0
3 years ago
Can anyone pls help me with this I’ll appreciate it. I’m trying to study for a test but I don’t know the answer to this.
forsale [732]

Answer:

okay so what you will do is where is says red giant you will write all about what it talks about red giants only, and the box plantary nebulas you will write about what is says about only planetary nebulas. x- hope this helps :)

Explanation:

7 0
3 years ago
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