What factors cause changes in the temperature of surface water

Which illustration represents the arrangement of particles in a gas?

Romashka [77]

Answer: the answer is c

Explanation:

just did it on ap3x

4 0

3 years ago

A car has a mass of 1520 kg. While traveling at 20 m⁄s, the driver applies the brakes to stop the car on a wet surface with a 0.

docker41 [41]

Answer:

(a)d₁ = 51.02 m

(b)d₂ =51.02m

Explanation:

Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration (m/s²)

Known data

m=1520 kg : mass of the car

μk= 0.4 : coefficient of kinetic friction

g = 9.8 m/s² : acceleration due to gravity

Forces acting on the car

We define the x-axis in the direction parallel to the movement of the car and the y-axis in the direction perpendicular to it.

W: Weight of the block : In vertical direction downward

FN : Normal force : In vertical direction upward

f : Friction force: In horizontal direction

Calculated of the W

W= m*g

W= 1520 kg* 9.8 m/s² = 14896 N

Calculated of the FN

We apply the formula (1)

∑Fy = m*ay ay = 0

FN - Wy = 0

FN = Wy

FN = 14896 N

Calculated of the f

f = μk* N= (0.4)* (14896 N )

f = 5958.4 N

We apply the formula (1) to calculated acceleration of the block:

∑Fx = m*ax , ax= a : acceleration of the block

- f = m*a

-5958.4 = (1520)*a

a = (-5958.4) / ((1520)

a = -3.92 m/s²

(a) displacement of the car (d₁)

Because the car moves with uniformly accelerated movement we apply the following formula to calculate the final speed of the block :

vf²=v₀²+2*a*d₁ Formula (2)

Where:

d:displacement (m)

v₀: initial speed (m/s)

vf: final speed (m/s)

Data:

v₀ = 20 m⁄s

vf = 0

a = --3.92 m/s²

We replace data in the formula (2) to calculate the distance along the ramp the block reaches before stopping (d₁)

vf²=v₀²+2*a*d ₁

0 = (20)²+2*(-3.92)*d ₁

2*(3.92)*d₁ = (20)²

d₁ = (20)² / (7.84)

d₁ = 51.02 m

(b) Different car

m₂ = 1.5 *1520 kg

μk₂= 0.4

W₂= m*g

W₂= (1.5) *1520 kg* 9.8 m/s² = (1.5)*14896 N

FN₂= (1.5)*14896 N

f= 0.4* (1.5)*14896 N

a = - f/m₂ = - 0.4* (1.5)*14896 N /(1.5) *1520

a = -3.92 m/s²

vf²=v₀²+2*a*d₂

vf=0 , v₀=20 m⁄s , a = -3.92 m/s²

d₂ = d₁ = 51.02m

6 0

4 years ago

If a rock is thrown upward on the planet Mars with a velocity of 10 ms, its height in meters seconds later is given by (a) Find

Delicious77 [7]

Answer:

$1) X(t)=Xo+So(t)+\frac{1}{2} g(t)^{2}$

2) S(Δt)=So+g(Δt)

Explanation:

I think the equation they gave you for the Height upon time in seconds it's (1), where if you see, you will find the gravity, that you should multiply by 2 because, its divided by two in (1) (that should be your (a)), then, once you find your gravity, you can use the equation (2) to know the Final Speed replacing g , at the time asked, remember that g is gravity, and Δt is the: final time- initial time.

so in the [1,2] interval of time, your Δt=1s, and in [1,1.5] is Δt=0,5s.

i hoped it helped you even though i cant give you the exact answer right now.

6 0

4 years ago

The eccentricity of an asteroid's orbit is 0.0442, and the semimajor axis is 1.12 x 1011 m. The Sun's center is at one focus of

nadezda [96]

Answer:

a. $d=99x10^{8}m$