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MatroZZZ [7]
3 years ago
6

Experiments performed with biological systems require a buffer that will not interfere with the stability and activities of the

biological components. In 1966, Norman Good and his colleagues began a series of investigations that established criteria for new zwitterionic buffers that would be optimal for experimentation with biological systems. These criteria included_____________.
a. pKa between 6 and 8
b. highly water soluble
c. minimally permeable to biological membranes
d. minimal effects of salt concentration
e. minimal effect of temperature on pKa (? pKa/°C)
Chemistry
1 answer:
SashulF [63]3 years ago
6 0

Answer:pKa between 6 and 8

b. highly water soluble

c. minimally permeable to biological membranes

d. minimal effects of salt concentration

Explanation:

Since most biological reactions occur at near neutral pH of 6-8, good buffers should have their pKa around this region. A good buffer must also be water soluble and not easily permeable to biological membranes to avoid to avoid accumulation of the buffer compound in cells. The buffer should also not be highly ionic to prevent issues due to salt effects.

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Explanation:

Please find the complete question in the attached file.

In the question, it uses the catalyst inside a process, which does not modify the process eigenvalues, however, it decreases the active energy with an enthalpy of -9kJmole, and also the power for activating decreases around 13 to 5 kJ mole, that's why the choice a is correct.

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If you have 3.48 x 1023 formula units of Lead (II) Permanganate, what is its mass?
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\large \boxed{\text{257 g}}

Explanation:

We can convert the formula units to moles and then use the molar mass to find the mass.

1. Moles of Pb(MnO₄)₂

n = 3.48 \times 10^{23}\text{ formula units} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ formula units}} = \text{0.5779 mol}

 

2. Mass of Pb(MnO₄)₂

\text{Mass} = \text{0.5779 mol} \times \dfrac{\text{445.07 g}}{\text{1 mol u}} = \text{257 g}\\\\\text{The mass of lead(II) permanganate is $\large \boxed{\textbf{257 g}}$}

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FromTheMoon [43]

Answer:

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In solving stoichiometric problems, it is mandatory to use moles as a conversion factor in calculating the mass of product formed or the mass of reactant consumed. We often read off the number of moles that reacted from the balanced reaction equation and then convert the reacting mass of species given to the number of moles of that specie that actually participated in the reaction in order to obtain any required information from a reaction.

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the radioactive half-life of an atom can depend on how it is bonded to other atoms. by changing the neighboring atoms that are bonded to a radioactive isotope, we can change its half-life.

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