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Varvara68 [4.7K]
4 years ago
12

Identify each of the atomic models described here.

Chemistry
2 answers:
bagirrra123 [75]4 years ago
5 0

Dalton model :) Hope this helped.

romanna [79]4 years ago
3 0

Answer:

Dalton model///////////////////////////

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Writing Prompt/Open-Ended Question
tino4ka555 [31]

Answer:

If you are given a chemical equation and specific amounts for each reactant in grams, you have to follow these steps, in order, to determine how much product can possilby be made:

1. Convert each reactant into moles of the product.

2. Determine which reactant is the limiting reactant.

3. Convert the moles of product, from the limiting reactant, to grams.

Explanation:

8 0
4 years ago
A sample of 508.4 grams of copper completely reacted with oxygen to form 572.4 grams of a copper oxide product. how many grams o
Svet_ta [14]

According to law of conservation of mass, mass can neither be destroyed nor created in a chemical reaction. Thus, sum of masses of reactants must be equal to sum of masses of products in a reaction.

The chemical reaction is as follows:

2Cu+O_{2}\rightarrow 2CuO

Here, sum of masses of Cu and oxygen gas should be equal to CuO formed.

2m_{Cu}+m_{O_{2}}=2m_{CuO}

Thus, mass of oxygen will be:

m_{O_{2}}=2(572.4-508.4)g=128 g

This can be further proved as follows:

The balanced chemical reaction is as follows:

2Cu+O_{2}\rightarrow 2CuO

Here, 2 moles of Cu completely reacts with 1 mole of O_{2} to give 2 moles of CuO.

Thus, 1 mole of Cu reacts with 0.5 moles of O_{2} .

The mass of Cu is 508.4 and molar mass is 63.546 g/mol, number of moles can be calculated as follows:

n=\frac{m}{M}=\frac{508.4 g}{63.546 g/mol}=8 mol

Thus, number of moles of  O_{2} reacting will be:

n_{O_{2}}=8\times 0.5 mol=4 mol

Molar mass of oxygen molecule is 32 g/mol thus, mass can be calculated as follows:

m=n×M=4 mol×32 g/mol=128 g/mol

This satisfies the law of conservation of mass.


7 0
3 years ago
What contribution did Niels Bohr make to atomic theory?
Bumek [7]

Answer:

C

Explanation

His greatest contribution is the atomic model

3 0
3 years ago
Hydrogen peroxide can act as either an oxidizing agent or a reducing agent depending on the species present in solution. Write t
Gekata [30.6K]

Answer:

Reduction: 2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)

Oxidation: H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻

Explanation:

In H₂O₂, hydrogen has the oxidation number +1 and oxygen the oxidation number -1.

In the reduction half-reaction (H₂O₂ is the oxidizing agent), H₂O₂ forms H₂O. The oxidation number of oxygen decreases from -1 to -2.

2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)

In the oxidation half-reduction (H₂O₂ is the reducing agent), H₂O₂ forms O₂. The oxidation number of oxygen increases  from -1 to 0.

H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻

3 0
3 years ago
Why isn't the ph at the equivalence point always equal to 7 in a neutralization titration?
Lunna [17]

The pH at the equivalence point always not equal to 7 in a neutralization titration when titration occur between weak acid and weak base , strong acid and weak base or strong base weak acid. The reason behind it is given as,

  • At equivalence point the product is present by reacting from acid and base.
  • So, when weak acid titrate with strong base then the solution will be weak base at equivalence point.

When strong acid is neutralize with strong base then it form neutral product at the equivalence point. Hence the final conclusion is that the pH of the solution in which titration is takes place between strong acid and strong base is 7 that is neutral left titration between all type of acids and bases ha pH not equal to 7 .

learn more about equivalence point

brainly.com/question/4518249

#SPJ4

7 0
1 year ago
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