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vekshin1
3 years ago
7

What state is nitrogen at 20 degree Celsius

Chemistry
1 answer:
Norma-Jean [14]3 years ago
3 0
Nitrogen becomes a liquid at 20 degrees celsius 
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Two aqueous sulfuric acid solutions containing 20.0 wt% H2SO4
kozerog [31]

Answer:

The feed ratio (liters 20%  solution/liter 60% solution) is 3,08

Explanation:

In this problem you have a 20,0 wt% H₂SO₄ and a 60,0 wt% H₂SO₄ solutions.

100 kg of 20% solution are 100kg/1,139 kg/L = <em>87,8 L </em>

100kg×20wt% = 20 kg H₂SO₄. In moles:

20 kg H₂SO₄ × (1 kmol/98,08 kg) = 0,2039 kmol H₂SO₄≡ <em>203,9 mol</em>

The final molarity 4,00M comes from:

\frac{203,9 moles+ Xmoles}{87,8L + Yliters} <em>(1)</em>

Where X moles and Y liters comes from 60,0 wt% H₂SO₄

100 L of 60,0 wt% H₂SO₄ are:

100L×\frac{1,498 kgsolution}{L}×\frac{60 kg H_{2}SO_{4}}{100kgSolution}×\frac{1kmol}{98,08kg H_{2}SO_{4}} = <em>0,9164 kmolH₂SO₄ ≡ 916,4 moles</em>

That means:

X/Y = 916,4/100 = 9,164 <em>(2)</em>

Replacing (2) in (1):

Y(liters of 60,0 wt% H₂SO₄) = <em>28,52 L</em>

Thus, feed ratio (liters 20%  solution/liter 60% solution):

87,8L/28,52L = <em>3,08</em>

I hope it helps!

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3 years ago
What is the state of matter for the outer core?
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The alchemical, medical, and technological traditions were precursors to chemistry. State a contribution that each made to the d
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Major contributions to health care have been made possible by chemistry. The development of new drugs involves chemical analysis and synthesis to form new compounds.

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To know more about Alchemy, refer to this link:

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4 0
2 years ago
Sodium carbonate (na2co3) is used to neutralize the sulfuric acid spill. how many kilograms of sodium carbonate must be added to
jenyasd209 [6]
<span>5.45 x 10^3 kg of sodium carbonate is needed to neutralize 5.04 kg of sulfuric acid. For this, I will assume you have pure H2SO4. So first, you need to calculate the molar mass of H2SO4 and Na2CO3. Lookup the atomic weights of all the elements involved. Atomic weight of Sodium = 22.989769 Atomic weight of Sulfur = 32.065 Atomic weight of Carbon = 12.0107 Atomic weight of Oxygen = 15.999 Atomic weight of Hydrogen = 1.00794 Molar mass of H2SO4 = 2 * 1.00794 + 32.065 + 4 * 15.999 = 98.07688 g/mol Molar mass of Na2CO3 = 2 * 22.989769 + 12.0107 + 3 * 15.999 = 105.987238 g/mol The balanced equation for the reaction of Na2CO3 with H2SO4 is Na2CO3 + H2SO4 => Na2SO4 + CO2 + H2O so for every mole of sulfuric acid to be neutralized, you need 1 mole of sodium carbonate. You can determine the number of moles of sulfuric acid you have and then calculate the mass of that many moles of sodium carbonate. But, there's an easier way. Just use the relative mass differences between sodium carbonate and sulfuric acid. So 105.987238 g/mol / 98.07688 g/mol = 1.080655 So that means for every kg of sulfuric acid, you need 1.080655 kg of sodium carbonate. Now do the multiplication. 5.04 x 10^3 kg * 1.080655 = 5.4465 x 10^3 kg. Since you only have 3 significant figures for your data, round the result to 3 significant figures, giving 5.45 x 10^3 kg</span>
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3 years ago
Look carefully at the animation. The moving items represents electrons.
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Electrons attract objects and pull toward
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4 years ago
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