Question

Write a balanced equation for the reaction of Al(H2O)63+ in aqueous KF. Include the physical states of each reactant and product in your equation. Use an equilibrium arrow between reactants and products. Ignore potassium ions.

Answer 1

Explanation:

The potassium fluoride will dissociate into potassium ions and fluoride ions in their aqueous solution.

$KF(aq)\rightarrow K^+(aq)+F^-(aq)$

So, when 1 mol of  hexaaqua aluminium (III) reacts with 6 moles of fluoride ion it gives 1 mole of hexafluoroaluminate(III).

The reaction is given as:

$Al(H_2O)_6^{3+}(aq)+6F^-(aq)\rightleftharpoons AlF_6^{3-}(aq)+6H_2O(l)$