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Reil [10]
3 years ago
14

Write a balanced equation for the reaction of Al(H2O)63+ in aqueous KF. Include the physical states of each reactant and product

in your equation. Use an equilibrium arrow between reactants and products. Ignore potassium ions.
Chemistry
1 answer:
olga2289 [7]3 years ago
3 0

Explanation:

The potassium fluoride will dissociate into potassium ions and fluoride ions in their aqueous solution.

KF(aq)\rightarrow K^+(aq)+F^-(aq)

So, when 1 mol of  hexaaqua aluminium (III) reacts with 6 moles of fluoride ion it gives 1 mole of hexafluoroaluminate(III).

The reaction is given as:

Al(H_2O)_6^{3+}(aq)+6F^-(aq)\rightleftharpoons AlF_6^{3-}(aq)+6H_2O(l)

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Consider water at 500 kPa and a specific volume of 0.2 m3/kg, what is the temperature (in oC)?
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Explanation:

We have the ideal gasses equation PV=nRT and the expression for the specific volume v=\frac{V}{m}, that is the inverse of the density, and for definition the number of moles is equal to the mass over the molar mass, that is n=\frac{m}{M}

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T=\frac{PvM}{R}

Now, we should convert all the quantities to the same units:

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500kPa*\frac{0.00986923}{1kPa}=4.93atm

-Convert 0.2\frac{m^{3}}{kg} to \frac{L}{kg}

0.2\frac{m^{3} }{kg}*\frac{1L}{1m^{3}}=0.2\frac{L}{kg}

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18\frac{g}{mol}=\frac{1kg}{1000g}=0.018\frac{kg}{mol}

Finally we can replace the values:

T=\frac{(4.93atm)(0.2\frac{L}{kg})(0.018\frac{kg}{mol})}{0.082\frac{atm.L}{mol.K}}

T=0.216K

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