Question

The monomer seen below is called ethylene. Through addition polymerization it can be made into polyethylene, which goes by the abbreviation PE. Determine the degree of polymerization (DP) of a PE polymer with a molecular weight of 223300 g/mol.

Answer 1

Answer:

The degree of polymerization, DP = 7961

Explanation:

Considering that:-

$Mass_{Polymer}=n\times Mass_{Monomer}$

Where, n is the degree of polymerization (DP)

Thus, Given that monomer of this polymer is:- ethylene

Molar mass of monomer, ethylene = 28.05 g/mol

Given that, Molar mass of the polymer = 223300 g/mol

Thus,

$223300=n\times 28.05$

$n=\frac{406000}{51}$

$n =7960.7843$

Thus, The degree of polymerization, DP = 7961