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Oksanka [162]
3 years ago
10

A uniform electric field has magnitude E and is directed in the negative x direction. The potential difference between point a (

at x= 0.50 m ) and point b (at x= 0.85 m ) is 300 V . Part A Which point, a or b, is at the higher potential?
Physics
1 answer:
kupik [55]3 years ago
6 0

Answer:

Point b is at the higher potential

Explanation:

Since it is given that electric field is directed in the negative x direction meaning that the potential is increasing on positive x  axis so b (x = 0.85) is at higher potential.

We also know that that the direction of Electric field is always from higher potential to lower potential so b must be at higher potential.

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What is the change in velocity of a 22-kg object that experiences a force of 15 N for
vagabundo [1.1K]

Answer:

Force = mass × acceleration

Acceleration:

{ \tt{15 = (22 \times a)}} \\ { \tt{a =  \frac{15}{22}  \:  {ms}^{ - 2} }}

From first Newton's equation of motion:

{ \bf{v = u + at}}

Change = v - u:

{ \tt{v - u = (a \times t)}} \\ { \tt{v - u = ( \frac{15}{22} \times 1.2) }} \\ { \tt{v - u = 0.82 \:  {ms}^{ - 2} }}

3 0
3 years ago
A 40 g ball rolls around a 30 cm -diameter L-shaped track, shown in the figure, (Figure 1)at 60 rpm . What is the magnitude of t
levacccp [35]

Answer:

0.47 N

Explanation:

Here we have a ball in motion along a circular track.

For an object in circular motion, there is a force that "pulls" the object towards the centre of the circle, and this force is responsible for keeping the object in circular motion.

This force is called centripetal force, and its magnitude is given by:

F=m\omega^2 r

where

m is the mass of the object

\omega is the angular velocity

r is the radius of the circle

For the ball in this problem we have:

m = 40 g = 0.04 kg is the mass of the ball

\omega =60 rpm \cdot \frac{2\pi rad/rev}{60 s/min}=6.28 rad/s is the angular velocity

r = 30 cm = 0.30 m is the radius of the circle

Substituting, we find the force:

F=(0.040)(6.28)^2(0.30)=0.47 N

3 0
3 years ago
In Newton’s second law, if the net force acting on object doubles. The object’s Will also double
Anna71 [15]

Answer: Explanation:

If the net force on an object is doubled, its acceleration will double If the mass of an object is doubled, the acceleration will be halved .

3 0
3 years ago
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enyata [817]
As we sit in a chair, Action force will be only in one direction and that direction would be downward only.

In short, Your Answer would be Option A

Hope this helps!
5 0
4 years ago
Read 2 more answers
A brick with a mass of 20 kg and a weight of 196 N is released on a frictionless plane at an angle of 30°. What is the accelerat
Veronika [31]

Answer:4.9m/s^2

Basically answer A

Explanation:

6 0
4 years ago
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