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klasskru [66]
2 years ago
15

Two objects gravitationally attract with a force of 70N. If the masses of both of the objects are increased by 15x and the dista

nce between their centers change by a factor of 12x, then the new force of attraction is ___ N.
a. 1.56 N
b. 109.38 N
c. 7.29 N
d. 1312.5 N
Physics
1 answer:
erastova [34]2 years ago
7 0
(B is the answer!!
I took the test and I got a 100! Hope this helps
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A steel bar of rectangular cross section (1.5 in. 2 3 .0 in.) carries a tensile load P (see fig- ure). The allowable stresses in
lukranit [14]

Explanation:

Value of the cross-sectional area is as follows.

        A = 1.5 \times 2.30

           = 3.45 in^{2}

The given data is as follows.

          Allowable stress = 14,500 psi

          Shear stress = 7100 psi

Now, we will calculate maximum load from allowable stress as follows.

           P_{max} = \sigma_{a}A

                       = 14500 \times 3.45

                       = 50025 lb

Now, maximum load from shear stress is as follows.

           P_{max} = 2 \times \tau_{a} \times A

                      = 2 \times 7100 \times 3.45

                      = 48990 lb

Hence, P_{max} will be calculated as follows.

       P_{max} = min((P_{max})_{\sigma}, (P_{max})_{\tau})

                  = 48990 lb

Thus, we can conclude that the maximum permissible load P_{max} is 48990 lb.

4 0
3 years ago
Under ideal conditions (no atmospheric interference of any kind), if I hit a golf ball at an angle of 25 degrees at an initial s
g100num [7]

Answer:

The required angle is (90-25)° = 65°

Explanation:

The given motion is an example of projectile motion.

Let 'v' be the initial velocity and '∅' be the angle of projection.

Let 't' be the time taken for complete motion.

Let 'g' be the acceleration due to gravity

Taking components of velocity in horizontal(x) and vertical(y) direction.

v_{x} =  v cos(∅)

v_{y} =  v sin(∅)

We know that for a projectile motion,

t =\frac{2vsin(∅)}{g}

Since there is no force acting on the golf ball in horizonal direction.

Total distance(d) covered in horizontal direction is -

d = v_{x}×t = vcos(∅)×\frac{2vsin(∅)}{g} = \frac{v^{2}sin(2∅) }{g}.

If the golf ball has to travel the same distance 'd' for same initital velocity v = 23m/s , then the above equation should have 2 solutions of initial angle 'α' and 'β' such that -

α +β = 90° as-

d = \frac{v^{2}sin(2α) }{g} = \frac{v^{2}sin(2[90-β]) }{g} =\frac{v^{2}sin(180-2β) }{g} = \frac{v^{2}sin(2β) }{g} .

∴ For the initial angles 'α' or 'β' , total horizontal distance 'd' travelled remains the same.

∴ If α = 25° , then

     β = 90-25 = 65°

∴ The required angle is 65°.

5 0
3 years ago
Read 2 more answers
you add equal amounts of heat to two identical cylinders containing equal amounts of the same ideal gas. cylinder a is allowed t
OleMash [197]

Temperature rise will be there in cylinder B more than in cylinder A because of internal energy.

what is internal energy?

The sum of the kinetic and chemical potential energies of all the particles in the system is the internal energy. Particles accelerate and pick up kinetic energy when energy is applied to increase the temperature.

Briefing:

Cylinder A uses the heat it absorbs to both work while expanding and to increase internal energy (or temperature).

While cylinder B solely uses the heat it absorbs to increase its internal energy 

As a result, cylinder B's temperature rise is greater than cylinder A's.

To know more about internal energy visit:

brainly.com/question/11278589

#SPJ4

3 0
1 year ago
which drawing below represents the electric field surrounding two objects that have equal magnitude changes of opposite polarity
Fantom [35]

Answer:

the 3rd one

Explanation:

j cause I think so

8 0
2 years ago
An atom of arsenic has how many electron-containing orbitals
irina [24]

Answer:

The Arsenic has three electron-containing orbitals. The orbitals s, p and d.

Explanation:

Arsenic is an element with an atomic number equal of 33, it means that it has 33 electrons in its orbitals in the following way:

1s^{2}

2s^{2}

2p^{6}

3s^{2}

3p^{6}

3d^{10}

4s^{2}

4p^{3}

Therefore, the Arsenic has three electron-containing orbitals (s, p d).

8 0
3 years ago
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