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Tems11 [23]
3 years ago
12

A large water tank is 3.75 m high and filled to the brim, the top of the tank open to the air. A small pipe with a faucet is att

ached to the side of the tank, 0.800 m above the ground. If the valve is opened, at what speed will water come out of the pipe?
Physics
1 answer:
Degger [83]3 years ago
5 0

Answer:

7.16 m /s

Explanation:

The depth of the small pipe attached with the side wall of tank from the surface of water

h =( 3.1 - .48 )m

= 2.62 m

velocity of flow of water= √ 2 g h

= √ 2 x 9.8 x 2.62

= 7.16 m /s

#need any question answered within secs/mins, hit me up and I got you!

#branilest

:) <3

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Electromagnetic waves do require a medium to travel.<br><br> True<br> False
pshichka [43]

Answer:

The Answer is false

Explanation:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

8 0
4 years ago
Read 2 more answers
An air conditioner has a power rating of 3000 W and is used daily. Its electrical
Anarel [89]

Answer:

5.714 hours / day

Explanation:

<u>Calculate the hours used in that week </u>

120000 / 3000 = 120 / 3 = 40 hours a week

<u>Calculate the amount it is used in one day</u>

40 / 7 = 5.71428571 hours or 5.714 hours/day

5 0
2 years ago
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A 1.0-μm-diameter oil droplet (density 900 kg/m3) is negatively charged with the addition of 39 extra electrons. It is released
GREYUIT [131]

Answer:

6.75\mu C/m^2

Explanation:

We are given that

Diameter,d=1\mu m=1\time 10^{-6} m

1\mu m=10^{-6} m

Radius,r=\frac{d}{2}=\frac{1}{2}\times 10^{-6}=0.5 \times 10^{-6} m

Density,\rho=900kg/m^3

Total number of electrons,n=39

Charge on electron =1.6\times 10^{-19} C

Total charge=q=ne=39\times 1.6\times 10^{-19}=62.4\times 10^{-19} C

Distance,s=2mm=2\times 10^{-3} m

Mass =density\times volume=900\times \frac{4}{3}\pi r^3=900\times \frac{4}{3}\pi(0.5\times 10^{-6})^3=4.7\times 10^{-16} kg

Initial velocity,u=0

Final speed,v=4.5 m/s

v^2-u^2=2as

(4.5)^2-0=2a(2\times 10^{-3})

20.25=4a\times 10^{-3}

a=\frac{20.25}{4\times 10^{-3}}=5062.5m/s^2

Force,F=ma

qE=ma

q(\frac{\sigma}{2\epsilon_0})=ma

\sigma=\frac{2\epsilon_0ma}{q}=\frac{2\times 8.85\times 10^{-12}\times 4.7\times 10^{-16}\times 5062.5}{62.4\times 10^{-19}}

\epsilon_0=8.85\times 10^{-12}

\sigma=6.75\times 10^{-6}C/m^2=6.75\mu C/m^2

6 0
3 years ago
What part of the gun position equipment supports all of the elevating parts of the gun?
BARSIC [14]
The gunstock it’s also called stock or shoulder stock
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3 years ago
Anaerobic metabolism:
goblinko [34]

Explanation:

B. leads to muscle strain.

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