Answer:
Moles = 0.5 mol
Solution:
Moles is related to mass as follow,
Moles = Mass / M.mass ----- (1)
Where;
Mass = 50 g
M.mass = Ca (40) + C (12) + O₃ (16)₃ = 100 g/mol
Putting values in equation 1,
Moles = 50 g ÷ 100 g.mol⁻¹
Moles = 0.5 mol
Answer:
1. 0.207 moles
2. 6.99 moles
3. 4.20 moles
4. 4.65 moles
5. 2.221 × 10²⁴ atoms
6. 2.221 × 10²⁴ atoms
7. 4.979 × 10^18 atoms
Explanation:
The number of moles and atoms can be calculated using the Avagadro's number, which is 6.02 × 10^23 atoms.
mole = number of atoms ÷ Avagadro's number.
1. Mole = 1.25 x 10²³ ÷ 6.02 × 10^23
mole of Boron = 0.207 × 10(23-23)
= 0.207 × 10^0
= 0.207 moles
2. Mole = 4.21 x 10²⁴ ÷ 6.02 × 10^23
mole of Aluminum = 0.699 × 10(24-23)
= 0.699 × 10^1
= 6.99 moles
3. Mole = 2.53 x 10²⁴ ÷ 6.02 × 10^23
mole of Argon = 0.420 × 10(24-23)
= 0.420 × 10^1
= 4.20moles
4. Mole = 2.80 x 10²⁴ ÷ 6.02 × 10^23
mole of Hydrogen = 0.465 × 10(24-23)
= 0.465 × 10^1
= 4.65 moles
5. Number of atoms of Na = 3.69 × 6.02 × 10²³
= 22.21 × 10²³
= 2.221 × 10²⁴ atoms
6. Number of atoms of Na = 3.69 × 6.02 × 10²³
= 22.21 × 10²³
= 2.221 × 10²⁴ atoms
7. Number of atoms of Co = 8.27 x 10⁻⁶ moles × 6.02 × 10²³ atoms
= 49.79 × 10^17
= 4.979 × 10^18 atoms
The base gram of the compound is 16.042
To find the new amount of grams, you need to multiply the amount of moles by the the base grams
16.042*.25=4.01
So one fourth of the compound is 4.01 grams of Carbon tetrahydride.
Answer:
508.8g
Explanation:
Mass of one mole= (12×12)+(24×1)+(2×12)
144+24+24=192g
Mass of 2.65 moles=192×2.65=508.8g