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marin [14]
4 years ago
15

A spring scale calibrated in kilograms is used to determine the density of a rock specimen. The reading on the spring scale is 0

.45 kg when the specimen is suspended in air and 0.36 kg when the specimen is fully submerged in water. If the density of water is 1000 kg/m3, the density of the rock specimen is_________.
Physics
1 answer:
denpristay [2]4 years ago
4 0

Answer:

5000 kg/m^3

Explanation:

Here. we are asked to calculate the density of the rock specimen.

we proceed as follows;

mass of water displaced is calculated by finding the difference between the actual and apparent masses

This has a value of 0.45kg - 0.36kg = 0.09kg

The rock and water that is displaced have exactly the same volume and thus their densities is the same. This makes the ratio of their masses to be the same

Ratio of masses is

0.45 / 0.09 = 5.0

Here we can see that the mass of the rock is five times the mass of the water so it must be five times denser

Thus, since the density of water is 1000 kg/m^3 , the density of rock is 5000 kg/m^3

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A girl lifts a 160-N load to a height of 1 min 0.5 s. How much power is used to lift the load?
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Answer: 320 W

Explanation:

P = W/t

W = F * d

F = 160 N

d = 1 m

t = 0.5 s

W = 160 * 1

W = 160 J

P = 160 J / 0.5 s

P = 320 W

8 0
3 years ago
What words does convection come from
ludmilkaskok [199]

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Explanation:

6 0
3 years ago
A solenoid 25.0 cmcm long and with a cross-sectional area of 0.550 cm^2 contains 460 turns of wire and carries a current of 90.0
ankoles [38]

Answer:

a.  B = 0.20T

b.  u = 17230.6 J/m³

c.  E = 0.236J

d.  L = 5.84*10^-5 H

Explanation:

a. In order to calculate the magnetic field in the solenoid you use the following formula:

B=\frac{\mu_o n i}{L}               (1)

μo: magnetic permeability of vacuum = 4π*10^-7 T/A

n: turns of the solenoid = 460

L: length of the solenoid = 25.0cm = 0.25m

i: current  = 90.0A

You replace the values of the parameters in the equation (1):

B=\frac{(4\pi*10^{-7}T/A)(460)(90.0A)}{0.25m}=0.20T

The magnetic field in the solenoid is 0.20T

b. The magnetic permeability of air is approximately equal to the magnetic permeability of vacuum. To calculate the energy density in the solenoid you use:

u=\frac{B^2}{2\mu_o}=\frac{(0.20T)^2}{2(4\pi*10^{-7}T/A)}=17230.6\frac{J}{m^3}

The energy density is 17230.6 J/m³

c. The total energy contained in the solenoid is:

E=uV           (2)

V is the volume of the solenoid and is calculated by assuming the solenoid as a perfect cylinder:

V=AL

A: cross-sectional area of the solenoid = 0.550 cm^2 = 5.5*10^-5m^2

V=(5.5*10^{-5}m^2)(0.25m)=1.375*10^{-5}m^3

Then, the energy contained in the solenoid is:

E=(17230.6J/m^3)(1.375*10^{-5}m^3)=0.236J

The energy contained is 0.236J

d. The inductance of the solenoid is calculated as follow:

L=\frac{\mu_o N^2 A}{L}=\frac{(4\pi*10^{-7}T/A)(460)^2(5.5*10^{-5}m^2)}{0.25m}\\\\L=5.84*10^{-5}H

The inductance of the solenoid is 5.84*10^-5 H

3 0
4 years ago
A 20 g sparrow flying toward a bird feeder mistakes the pane of glass in a window for an opening and slams into it with a force
Rama09 [41]
I found this using the app Socratic. When I took physics in high school it helped me so much.

5 0
3 years ago
The mole is 6.02 x 10 23 particles. If a person masses out the correct molar mass in grams for a substance then she would have a
Leto [7]

Answer:

1 mole of H2O is 18 grams (2 g H + 16 g Oxygen)

36 / 18 = 2

So 2 moles = 2 * 6.02E23 = 12.04E23 = 1.204E24

7 0
3 years ago
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