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Tamiku [17]
4 years ago
8

How does conduction differ from convection?

Physics
2 answers:
nataly862011 [7]4 years ago
3 0
Conduction has to be touching the two objects. Convection is not direct.
Elanso [62]4 years ago
3 0

for online classes : Conduction warms the atmosphere as fast-moving molecules come into contact with lower-energy molecules until all molecules are moving at about the same rate. As the atmosphere warms, molecules move apart. As the heated air flows, heat is transferred by convection from warm, low-pressure air to cooler, high-pressure air.

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The driver must stop and remain stopped to let a pedestrian cross at a crosswalk when the pedestrian is _____________.
RSB [31]

Answer: the correct option is B ( on the half of the road that the vehicle is traveling).

Explanation: according to Georgia Code About Pedestrians; The driver must stop and remain stopped to let a pedestrian cross at a crosswalk when the pedestrian is

on the half of the road that the vehicle is traveling.

4 0
3 years ago
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A bookcase has a base of 1 m long and 0.5 m wide. It has a mass of 300kg. Find the pressure it exerts on the floor in kPa.
Snezhnost [94]
1m*0.5m=0.5m^2\\
g=10\frac{m}{s^2}\\
300kg*10\frac{m}{s^2}=3000N\\
3000N--0.5m^2\\
\ \ x\ \ --\ 1\\
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4 0
3 years ago
If cooling occurred at the bottom of a lake instead of its surface, the lake
AlladinOne [14]
No because the top has more oxygen to it which will break the particles up and have them freeze easier.

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5 0
3 years ago
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g If you keep the launch angle fixed, but double the initial launch speed, what happens to the range?
kiruha [24]

Answer:

Range will become 4 times of initial range

Explanation:

Let the velocity of projection is u

And angle at which projectile is projected is \Theta

And acceleration due to gravity is g\ m/sec^2

So range of projectile is equal to R=\frac{u^2sin2\Theta }{g}........eqn 1

Now in second case it is given that velocity of launching is doubled

So new velocity u_{new}=2u

So new range will be equal to R_{new}=\frac{(2u)^2sin2\Theta }{g}=\frac{4u^2sin2\Theta }{g} .....eqn 2

Now dividing eqn 2 by eqn 1

\frac{R_{new}}{R}=\frac{4u^2sin2\Theta }{g}\times \frac{g}{u^2sin2\Theta }

R_{new}=4R

So if we double the initial launch speed then range will become 4 times

4 0
4 years ago
El segundero de un reloj tiene 2cm de longitud. Determínese, para un punto en el extremo libre de la manecilla (considerando =
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Answer:

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Step-by-step explanation:

Answer:

Step-by-step explanation:

Explanation:geman tick kokkok

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6 0
3 years ago
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