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Digiron [165]
3 years ago
9

What can you conclude about plastic and copper from the observations given above?

Physics
1 answer:
ipn [44]3 years ago
5 0
What are the "observations above" in this question?
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How much force is needed to accelerate a 3 kg skateboard at 5 m/s2
Umnica [9.8K]

The problem is fairly simple if you use the formula.

Formula: Force = (mass) x (acceleration)

3 x 5 = 15 newtons

Note: 3 kg is the mass of the skateboard, and 5 m/s2 is the acceleration.

Answer: 15 newtons

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Kaylis [27]

Answer:ok

Explanation:

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What is fiery about igneous rocks?
xz_007 [3.2K]
It is fiery because it is cooled molten magma
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-In the Bohr model, as it is known today, the electron is imagined to move in a circular orbit about a stationary proton. The fo
vampirchik [111]

Answer:

4.3859007196\times 10^{-9}\ m

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

v = Velocity of electron = 2.4\times 10^5\ m/s

q = Charge of electron = 1.6\times 10^{-19}\ C

m = Mass of electron = 9.11\times 10^{-31}\ kg

r = Radius

The electrical and centripetal force will balance each other

\dfrac{kq^2}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow r=\dfrac{kq^2}{mv^2}\\\Rightarrow r=\dfrac{8.99\times 10^9\times (1.6\times 10^{-19})^2}{9.11\times 10^{-31}\times (2.4\times 10^5)^2}\\\Rightarrow r=4.3859007196\times 10^{-9}\ m

The radius of the orbital is 4.3859007196\times 10^{-9}\ m

4 0
3 years ago
A bullet of mass m and speed v is fired at, hits and passes completely through a pendulum bob of mass M on the end of a stiff ro
dexar [7]

Required value of initial speed of the bullet be ( 4M/m)√(gL).

Given parameters:

Mass of the bullet =m.

Mass of the bob of the pendulum = M.

speed of the bullet before collision = v

Speed of the bullet after collision = v/2.

Length of the pendulum stiff rod = L.

Let speed transmitted to the pendulum be u.

Using principle of conservation of momentum:

mv = Mu + mv/2

⇒ Mu = mv/2

⇒ u = (m/M)v/2

We know that: to make the bob over the top of the trajectory without falling backward in its circular path, required speed be = √(4gL). [ where g = acceleration due to gravity]

To be minimum initial speed the bullet must have in order for the pendulum bob to just barely swing through a complete vertical circle:

u = √(4gL)

⇒  (m/M)v/2 = √(4gL)

⇒ v =( 4M/m)√(gL).

Hence, minimum required  speed of the bullet be ( 4M/m)√(gL).

Learn more about speed here:

brainly.com/question/28224010

#SPJ1

7 0
1 year ago
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