Answer:
Given that,
- Power = 2000 W
- time = 60 seconds
- distance= 10m
Power = work done ÷ time
Here, since the movement is vertical, w = mgh
So,
Power = mgh÷t
2000 = (m × 9.8 ×10) ÷ 60
m = (2000 ×60) ÷98
m = 1224.5kg
Answer:
The work done is L= 49.83 Joules
Explanation:
m= 2.44kg
d= 1.55m
α= 69.6°
g= 9.8 m/s²
μ= 0.691
F= ?
Fy= F*sin(α)
Fx= F*cos(α)
Fr= μ * Fx
Fr= μ * F*cos(α)
W= m*g
W= 23.91 N
Fy - W - Fr = 0
F*sin(α) - W - μ * F*cos(α) = 0
F* ( sin(α) - μ *cos(α) ) = W
F= W / ( sin(α) - μ *cos(α) )
F= 34.3 N
L= Fy * d
L= 49.83 J
A group of protons and neutrons that are surrounded by electrons
Answer:
The spring stretched by x = 13.7 cm
Explanation:
Given data
Mass = 3 kg
k = 120 
Angle 
= 34°
From the free body diagram
Force acting on the box = mg sin
⇒ F = 3 × 9.81 × 
⇒ F = 16.45 N ------- (1)
Since box is attached with the spring so a spring force also acts on the box.
= k x
= 120 
-------- (2)
The net force acting on the body is given by
Since acceleration of the box is zero so
Put the values from equation (1) & (2) we get
16.45 = 120
x = 0.137 m
x = 13.7 cm
Therefore the spring stretched by x = 13.7 cm
Archimedes found a piece of gold and a piece of silver with exactly the same mass. He dropped the gold into a bowl filled to the brim with water and measured the volume of water that spilled out. Then he did the same thing with the piece of solver. Although both metals had the same mass, the silver gad a larger volume; therefore, it displaced more water than the gold did. That's because the silver was less dense than gold. Afterwards he applied the same method to the crown for the king he served who had got a new crown from a jeweler who gave it to him. Archimedes found a piece of pure gold that had the same mass as the crown. He placed the pure gold chuck and the crown in water, one at a time. The crown displaced more water the piece of gold. Therefore, its density was less than pure gold.
