The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.
<h3>
Total capacitance of the circuit</h3>
The total capacitance of the circuit is calculated as follows;
Capacitors in series;
1/Ct = 1/8 + 1/7.5
1/Ct = 0.25833
Ct = 3.87 mF
Capacitors is parallel;
Ct = 3.87 mF + 12 mF + 15 mF
Ct = 30.87 mF
Ct = 0.03087 F
<h3>Charge in each capacitor</h3>
Q = CV
Q = 0.03087 x 12
Q = 0.37 C
Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.
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Answer:

Explanation:
The given data in the question is
Magnetic field : 
Turns : 
Length : 
So, number of turns per unit length :



If current is I , then magnetic field is given by

Also,

Insert the values


The current will be 
Answer:
Required charge
.

Explanation:
Given:
Diameter of the isolated plastic sphere = 25.0 cm
Magnitude of the Electric field = 1500 N/C
now
Electric field (E) is given as:

where,
k = coulomb's constant = 9 × 10⁹ N
q = required charge
r = distance of the point from the charge where electric field is being measured
The value of r at the just outside of the sphere = 
thus, according to the given data

or

or
Required charge
.
Now,
the number of electrons (n) required will be

or

or

Answer:
The answer to your question is:
a) h max = 529.7 m
b) t = 20.4 s
c) t = 20.6 s
Explanation:
a) h max = -(vo)² / 2g
= 100² / 2(9.81)
= 10000 / 19.62
= 509.7 m
total height = 509.7 + 20 = 529.7 m
b)
h = gt² / 2
t = √ 2h / g
t = √ 2(509.7)/9.81
t = √ 103.91
t = 10.19 s
total time = 2 x t = 2 x 10.19 = 20.4 s
c)
h = vot + 1/2gt²
20 = 100t + 1/2(9.91) t²
4.9t² + 100 t -20 = 0 quadratic equation
t = 0.19 s
Total time = 0.19 + 20.4 = 20.6 s