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DiKsa [7]
2 years ago
11

What components of the atom are found outside of the nucleus? protons electrons neutrons all are found in the nucleus

Physics
2 answers:
Montano1993 [528]2 years ago
6 0
The components of an atom found outside the nucleus are electrons.
AlladinOne [14]2 years ago
5 0

the answer is electrons. this is proof checked and I guarantee this is the correct answer. hope this helped :)

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A coin and feather are dropped in a moon. what will fall earlier on ground.give reasons.if they are dropped in the earth,which o
Sergeeva-Olga [200]

Answer:

  • on the moon, they will fall at the time
  • on earth, the coin will fall faster to the ground

Explanation:

A coin and feather dropped in a moon experience the same acceleration due to gravity as small as 1.625 m/s², and because of the absence of air resistance both will fall at the same rate to the ground.

If the same coin and feather are dropped in the earth, they will experience the same acceleration due to gravity of 9.81 m/s² and because of the presence of air resistance, the heavier object (coin) will be pulled faster to the ground by gravity than the lighter object (feather).

4 0
2 years ago
Is a electron a positively charged, negatively charged, or a neutral particle
Effectus [21]
An electron is negatively charged.
3 0
3 years ago
Automobiles must be able to sustain a frontal impacl The automobile design must allow low speed impacts with little sustained da
valentinak56 [21]

Answer: the effective design stiffness required to limit the bumper maximum deflection during impact to 4 cm is 3906250 N/m

Explanation:

Given that;

mass of vehicle m = 1000 kg

for a low speed test; V = 2.5 m/s

bumper maximum deflection = 4 cm = 0.04 m

First we determine the energy of the vehicle just prior to impact;

W_v = 1/2mv²

we substitute

W_v = 1/2 × 1000 × (2.5)²

W_v = 3125 J

now, the the effective design stiffness k will be:

at the impact point, energy of the vehicle converts to elastic potential energy of the bumper;

hence;

W_v = 1/2kx²

we substitute

3125 = 1/2 × k (0.04)²

3125 = 0.0008k

k = 3125 / 0.0008

k = 3906250 N/m

Therefore, the effective design stiffness required to limit the bumper maximum deflection during impact to 4 cm is 3906250 N/m

3 0
2 years ago
Saatlemati
vodomira [7]

Answer:

what are u asking there isnt a question

3 0
2 years ago
NASA plans to launch a new satellite to orbit the Earth. As the satellite is launched the thrust of the hot exhaust gas is pushe
Leya [2.2K]

Answer:

A    

Explanation:

6 0
3 years ago
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