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PilotLPTM [1.2K]
3 years ago
14

Why do you need friction to walk?

Physics
2 answers:
Goshia [24]3 years ago
5 0

Answer:

The force of friction is a necessary force which helps us to walk on ground. The friction is generated between the shoes and the road. We press the ground and as a reaction the ground pushes us forward. The force of friction between sole and ground provides the necessary grip which pushes us forward

Explanation:

Don't copy word for word if your sending as paragraph answer

Ludmilka [50]3 years ago
3 0

Friction can be a useful force because it prevents our shoes slipping on the pavement when we walk and stops car tyres skidding on the road. When you walk, friction is caused between the tread on shoes and the ground. This friction acts to grip the ground and prevent sliding. Sometimes we want to reduce friction.

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Can sound travel through a tree
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What's the weight of a 30x30x50 cm body with the density of 1.8/cm cube?
grin007 [14]

Answer:

The weight of the body, W = 793.8 m/s²

Explanation:

Given,

The volume of the body, v = 45,000 cm³

The density of the body, ρ = 1.8 g/cm³

The mass of the body is given by the formula,

                                  m = ρ x v

                                      = 1.8 g/cm³ x 45,000 cm³

                                      = 81,000 g

Hence, the mass of the body is m = 81 kg

The weight of the body,

                                           W = m x g

                                                = 81 kg x 9.8 m/s²

                                                = 793.8 m/s²

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3 0
3 years ago
A 5 kg rock is lifted 3m find amount of work done <br><br> a= 98 J
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Answer:

How long would it take a machine to do 13,000 joules of work if the power rating ... An object gains 15 joules of potential energy as it is lifted vertically 5.0 meters. ... As the time required to do a given quantity of work decreases, the power ... How much work is being done to the system by the person of the sled moves 10 m?

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3 years ago
A car is traveling at 15m/s on a horizontal road. the brakes are applied and the car skids to a stop in 4.0s . the coefficient o
iren2701 [21]

Answer:

the coefficient of Kinetic friction between the tires and road is 0.38

Option A) .38 is the correct answer

Explanation:

Given that;

final velocity v = 0

initial velocity u = 15m/s

time taken t = 4 s

acceleration  a = ?

from the equation of motion        

v   =   u   +   at

we substitute

0 = 15 + a × 4

acceleration a = -15/4 =  - 3.75 m/s²    

the negative sign tells us that its a  deacceleration so the sign can be ignored.

Deacceleration due to friction a = μ × g

we substitute

3.75 = μ × 9.8    

μ = 3.75 / 9.8 = 0.3826 ≈ 0.38

Therefore the coefficient of Kinetic friction between the tires and road is 0.38

Option A) .38 is the correct answer

8 0
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