Answer:
The speed of the wave as it travelled through the brass bell is;
B. 4,700 m/s
Explanation:
The given parameters are;
The wavelength of the sound wave produced from the brass bell, 
= 3.5 m
The wavelength of the wave in the brass bell, 
= 47 m
The frequency of the wave in the brass bell, f = 100 Hz
The given equation for wave speed, v = f × λ
Therefore, the speed of the wave as it travelled through the brass bell, 
, is given as follows;
= f × = 100 Hz × 47 m = 4,700 m/s
The speed of the wave as it travelled through the brass bell = = 4,700 m/s
<span>The magnitude of a is 1.5
The magnitude of b is -3
The magnitude of the vector is
</span>√(1.5² + (-3)²) = 3.35
<span>The angle is
</span>θ = tan⁻¹ (-3/1.5) = 63.43°
<span>The vector is drawn with a magnitude of 3.35 and an angle of 63.43</span>°.
The electromotive force (∈) = 2 V
<h3>Further explanation</h3>
Given
I=2 A
t = 30 s
E = 120 J
Required
The electromotive force (∈)
Solution
The electromotive force : the potential difference between two electrodes in galvanic cell
Can be formulated :
E = energy, J
Q = charge , Coulomb = i.t
Answer: +2 e
Explanation: Net charge of a system is sum of charges on all the constituents of the system.
The system contains two spheres. Charge on one sphere is:
q₁ = +6 e
Charge on the second sphere is:
q₂ = -4 e
Net charge of the system is:
q = q₁ + q₂
q = +6 e + (-4 e) = + 2 e
Thus, the net charge of system is +2 e.
<span>The correct answer is all mentioned because all have the characteristics that apply in theories of the properties of matter and their physical behaviors, which encompass mass, temperature, smell, and volume.</span>
