Answer:
The forces of push and pull
Explanation:
In the egg drop experiment, the egg is balanced on top of a toilet paper tube and balanced on a pan. The pan itself is placed on top of a glass of water. When the experimenter uses his hands to push the pan, the force of gravity pulls the egg downwards making it move down, right into the glass of water.
So the two forces which are applied in opposite directions are;
1. The force of push applied horizontally by the hand when it pushes the pan away, and
2. The force of pull caused by gravity which makes the egg move vertically downwards.
Answer:
132 N
Explanation:
Given that a 1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail
From Newton 2nd law of motion,
Change in momentum = impulse.
Change in momentum = m( V - U )
Substitute all the parameters into the formula
Change in momentum = 1.1 ( 4.5 - 1.5 )
Change in momentum = 1.1 × 3
Change in momentum = 3.3 kgm/s
Impulse = Ft
That is,
Ft = 3.3
Substitute time t into the formula above
F × 0.025 = 3.3
F = 3.3 / 0.025
F = 132 N
Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.
Answer:
25.8 lb/in²
Explanation:
Gay-Lussac's law tells us that given an ideal gas of a certain mass has a constant volume, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.
Answer:
current is 13.88 A
Explanation:
given data
no of loops = 50 loops
resistance = 40 Ω
R = 15.0 Ω
I = 5.0 amp
N = 18
to find out
rms current
solution
we will apply here transformed principle that is
v(s) / v(p) = I(p) / I(s) = N(s) / N(p) ....................1
here p is primary and s is secondary
put here all these value
5 / I(s) = 18 / 50
I(s) = 250 /18
I(s) = 13.88
so current is 13.88 A
