Answer:
1. The field inside the shell is 0; TRUE
2. The field for r>R will be the same as a field for the point charge Q, at the origin: TRUE
3. only positive charges can be on the outside surface: FALSE (Negative can too!!!)
4. The field on the outside is perpendicular to the surface: TRUE
Explanation:
Given Information:
Power of bulb = w = 25 W
atts
distance = d = 9.5 cm = 0.095 m
Required Information:
Radiation Pressure = ?
Answer:
Radiation Pressure =7.34x10⁻⁷ N/m²
Explanation:
We know that radiation pressure is given by
P = I/c
Where I is the intensity of radiation and is given by
I = w/4πd²
Where w is the power of the bulb in watts and d is the distance from the center of the bulb.
So the radiation pressure becomes
P = w/c4πd²
Where c = 3x10⁸ m/s is the speed of light
P = 25/(3x10⁸*4*π*0.095²)
P = 7.34x10⁻⁷ N/m²
Therefore, the radiation pressure due to a 25 W bulb at a distance of 9.5 cm from the center of the bulb is 7.34x10⁻⁷ N/m²
Answer:
first law is your answer, if I'm not wrong
Answer:
D. Newton is a derived unit.
Answer:
Given:
Initial velocity of the asteroid, v = 19.9 km/s = 19900 m/s
(since, 1km = 1000 m)
Final velocity of the asteroid, v' = - 18.3 km/s = -18300 m/s
time period, T = 1.97 years
Solution:
(a). Total change in velocity, :
= v' - v
= - 18300 - 19900 = - 38200 m
here, negative sign is indicative of the fact that the motion of the asteroid is in the downward direction.
(b) Asteroid's average acceleration, a:
a =
a =
a =
Here, the negative sign is the indication of deceleration of the asteroid in the downward direction.