The electric potential energy of the charge is reduced because it decreases with increase in the distance between charges.
<h3>What is electric potential energy?</h3>
Electric potential energy can be defined as the energy needed to move a charge against an electric field.
It is calculated using the formula;
U = Kq1 q2 ÷ r
Where Q = electric potential energy
k = Coulombs constant
q1 and q2 = charges
r = distance of separation
Electric potential energy is inversely proportional to the distance of separation of the charges.
If the distance of the charges changes from 3mm to 6mm, then the electric potential energy of the charges is reduced because it decreases with increase in the distance of the charges.
Therefore, the electric potential energy of the charge is reduced because it decreases with increase in the distance between charges.
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Answer: b is sedimentary. c is metamorphic. and a is igneous.
Explanation:
Answer:
Q = - 256 X 10⁻⁷ C .
Explanation:
Electric field due to a charge Q at a distance d from the center is given by the expression
E = k Q /d² Where k is a constant and it is equal to 9 x 10⁹
Put the given value in the equation
9 x 10² = 
Q = 
Q = - 256 X 10⁻⁷ C .
It will be negative in nature as the field is directed towards the center.
Answer:
c) equals V
Explanation:
This is because, since the isolated, irregularly shaped piece of platinum is in electric equilibrium, the electric potential at all points on its surface is V. So that, the potential difference across any point is zero. This implies that diametrically opposite sides have the same potential and thus, the potential at other points of the surface is V since it is in electric equilibrium.
