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4 years ago

Simplify: (100 m)/(26 s)

Chemistry

2 answers:

podryga [215]4 years ago

4 0

100m/26s=50m/13s

50m/13s=3.846m/s

Ray Of Light [21]4 years ago

3 0

Answer: The correct answer is 3.846 m/s

Explanation:

We are given an expression:

(100 m)/(26 s)

The '/' symbol represents the division operation. The units are treated in the same way as the numerical values.

Evaluating the value of the expression, we get:

$\Rightarrow \frac{100m}{26s}=3.846m/s$

Hence, the correct answer for the given expression is 3.846 m/s

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A mixture of so2(g) and o2(g), formed by the complete decomposition of so3(g), is collected over water at 34°c at a total pressu

Sedbober [7]

The decomposition of so3 to so2 gas and o2 gas can be described in the balanced chemical equation:

2so3(g) = 2 so2 (g) + 02(g).

so assuming a complete reaction, the ratio of so2 gas to total products is 2/3 while that of 02 is 1/3.

Subtracting water's water vapor pressure, 760-40 mm hG = 720 mm Hg.

then the products partial pressures are

so2 = 2/3 * (720) = 480 mm Hg.
o2 = 720-480 = 240 mm Hg.

8 0

3 years ago

What is meant by the term compound? Provide an example

PIT_PIT [208]

Answer:

I hope it helps

Explanation:

When two or more elements chemically combine in a fixed ratio by mass, the obtained product is known as a compound. Compounds can be defined as substances consisting of 2 or more different types of elements in a fixed ratio of its atoms. When the elements combine, some individual property of the elements is lost and the newly formed compound has new properties.Chemical Formula: Compounds are represented by their chemical formula. A chemical formula is a symbolic representation of the proportions of atoms that constitute a particular chemical compound.The chemical formula of water is H2O which shows two atoms of hydrogen and one atom of oxygen have combined to form one molecule of H2O. The chemical formula for common salt is NaCl which shows one atom of sodium and one atom of chlorine combine to form one molecule of NaCl.

6 0

4 years ago

Organic reactions proceed at a very _______ rate

Savatey [412]

ANSWER:

Organic reactions proceed at a very SLOWER rate.

Reasoning:

Organic reactions are chemical reactions involving organic compounds. They are less soluble in water than inorganic compounds. Therefore, organic compounds react at a slower rate and produce a much more complex set of products than inorganic compounds.

6 0

3 years ago

What is the % by mass of oxygen in Mg(NO3)2 ?

Mashcka [7]

Answer:

72.71 %

Explanation:

For oxygen: mass % O = (mass of 1 mol of oxygen/mass of 1 mol of CO2) x 100. mass % O = (32.00 g / 44.01 g) x 100. mass % O = 72.71 %

HOPED THIS HELPED YOU OUT

A brainliest is always appreciated.

5 0

3 years ago

Determine the empirical formula for a compound that is 70.79% carbon, 8.91% hydrogen, 4.59% nitrogen, and 15.72% oxygen. determi

IceJOKER [234]

Hello!

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100g solution)

C: 70.79% = 70,79 g
H: 8.91% = 8.91 g
N: 4.59% = 4.59 g
O: 15.72% = 15.72 g

Let us use the above mentioned data (in g) and values will be converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:

$C: \dfrac{70.79\:\diagup\!\!\!\!\!g}{12\:\diagup\!\!\!\!\!g/mol} \approx 5.89\:mol$

$H: \dfrac{8.91\:\diagup\!\!\!\!\!g}{1\:\diagup\!\!\!\!\!g/mol} = 8.91\:mol$

$N: \dfrac{4.59\:\diagup\!\!\!\!\!g}{14\:\diagup\!\!\!\!\!g/mol} \approx 0.328\:mol$

$O: \dfrac{15.72\:\diagup\!\!\!\!\!g}{16\:\diagup\!\!\!\!\!g/mol} = 0.9825\:mol$

We note that the values found above are not integers, so let's divide these values by the smallest of them, so that the proportion is not changed, let's see:

$C: \dfrac{5.89}{0.328}\to\:\:\boxed{C\approx 18}$

$H: \dfrac{8.91}{0.328}\to\:\:\boxed{H\approx 27}$

$N: \dfrac{0.328}{0.328}\to\:\:\boxed{N\approx 1}$

$O: \dfrac{0.9825}{0.328}\to\:\:\boxed{O\approx 3}$

Thus, the minimum or empirical formula found for the compound will be:

 $\boxed{\boxed{C_{18}H_{27}N_1O_3\:\:or\:\:C_{18}H_{27}NO_3}}\end{array}}\qquad\checkmark$

I hope this helps. =)

5 0

3 years ago