The decomposition of so3 to so2 gas and o2 gas can be described in the balanced chemical equation:
2so3(g) = 2 so2 (g) + 02(g).
so assuming a complete reaction, the ratio of so2 gas to total products is 2/3 while that of 02 is 1/3.
Subtracting water's water vapor pressure, 760-40 mm hG = 720 mm Hg.
then the products partial pressures are
so2 = 2/3 * (720) = 480 mm Hg.
o2 = 720-480 = 240 mm Hg.
<span>ANSWER:
Organic reactions proceed at a very SLOWER rate.
Reasoning:
</span><span>Organic reactions are chemical reactions involving organic compounds. They are less soluble</span> in water than inorganic compounds. Therefore, organic compounds react at a slower rate and produce a much more complex set of products than inorganic compounds.
Answer:
72.71 %
Explanation:
For oxygen: mass % O = (mass of 1 mol of oxygen/mass of 1 mol of CO2) x 100. mass % O = (32.00 g / 44.01 g) x 100. mass % O = 72.71 %
HOPED THIS HELPED YOU OUT
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Hello!
We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100g solution)
C: 70.79% = 70,79 g
H: 8.91% = 8.91 g
N: 4.59% = 4.59 g
O: 15.72% = 15.72 g
Let us use the above mentioned data (in g) and values will be converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:




We note that the values found above are not integers, so let's divide these values by the smallest of them, so that the proportion is not changed, let's see:




T<span>hus, the minimum or empirical formula found for the compound will be:
</span>
I hope this helps. =)