Answer:
The enthalpy change during the reaction is -84 kJ/mole.
Explanation:
First we have to calculate the heat gained by the solution.
where,
Q = heat gained = ?
m = mass of the solution = 100.0 g
c = specific heat =
= final temperature =
= initial temperature =
Now put all the given values in the above formula, we get:
Now we have to calculate the enthalpy change during the reaction.
where,
= enthalpy change = ?
Q = heat gained = 420 J
n = number of moles silver nitrate= n
Molarity of the silver nitrate solution = M = 0.100 M
Volume of the silver nitrate solution = V = 50.0 mL = 0.050 L
(1 kJ = 1000 J)
Therefore, the enthalpy change during the reaction is -84 kJ/mole.