1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NARA [144]
3 years ago
10

Name MgSo4.7H2O /Cs3PO4.H2O

Chemistry
1 answer:
Radda [10]3 years ago
5 0

Answer:

MgSo4.7H2O = Magnesium sulfate

Cs3PO4.H2O = Cesium Phosphate

Hope this helps!

You might be interested in
Need help fast please I am timed and giving 47 points.
Leokris [45]

Answer:

C

Explanation:

6 0
3 years ago
Read 2 more answers
Which is always going to be the highest ionization energy?
Law Incorporation [45]

Answer: I think it's B.

Explanation:

4 0
1 year ago
If 175mL of oxygen is produced at STP, how many grams of hydrogen peroxide, H2O2
Vlad [161]

Answer:

0.53g

Explanation:

We'll begin by converting 175mL to L. This is illustrated below:

1000mL = 1L

Therefore 175mL = 175/1000 = 0.175L

Next, we shall calculate the number of mole of O2 that occupy 0.175L. This is illustrated below:

1 mole of O2 occupy 22.4L at stp.

Therefore, Xmol of O2 will occupy 0.175L i.e

Xmol of O2 = 0.175/22.4

Xmol of O2 = 7.81×10¯³ mole

Therefore, 7.81×10¯³ mole of O2 occupy 175mL.

Next, we shall determine the number of mole of H2O2 that decomposed to produce 7.81×10¯³ mole of O2. This is illustrated below:

2H2O2 —> 2H2O + O2

From the balanced equation above,

2 moles of H2O2 decomposed to produce 1 mole of O2.

Therefore, Xmol of H2O2 will decompose to produce 7.81×10¯³ mole of O2 i.e

Xmol of H2O2 = 2 x 7.81×10¯³

Xmol of H2O2 = 1.562×10¯² mole

Therefore, 1.562×10¯² mole of H2O2 decomposed in the reaction.

Finally, we shall convert 1.562×10¯² mole of H2O2 to grams. This is illustrated below:

Molar mass of H2O2 = (2x1) + (16x2) = 34g/mol

Mole of H2O2 = 1.562×10¯² mole

Mass of H2O2 =..?

Mole = mass /Molar mass

1.562×10¯² = mass /34

Cross multiply

Mass of H2O2 = 1.562×10¯² x 34

Mass of H2O2 = 0.53g

Therefore, 0.53g of Hydrogen peroxide, H2O2 were decomposition in the reaction.

3 0
3 years ago
Solution A has twice as much solute as solution B is it possible for the solutions to have the same concentration
pishuonlain [190]
Yes. As long as the ratio of solute and solvent is same for both solution, the solution has the same concentration. for example, solution A has 2 ml of water, and 1 ml of sucrose. Solution B has 4ml of water and 2ml of sucrose. Both has a ratio of water to sucrose by 2 : 1. they have the same concentration of 50% sucrose. 
5 0
3 years ago
You've probably heard that some types of bacteria can cause infections and make you sick.
Novosadov [1.4K]

Answer:

<u>(A) Plants would probably not have enough nitrogen.</u>

Explanation:

<em>According to the passage, bacteria help us digest our food and make yogurt. But it is the bacteria in the soil specifically that "Cycle nitrogen through the ecosystem, which plants rely on"</em>

6 0
2 years ago
Other questions:
  • When performing a flame test using the method described in the manual, you complete the flame test of KNO3 and find a yellow col
    7·1 answer
  • The reaction of fluorine with ammonia produces dinitrogen tetrafluoride and hydrogen fluoride.
    11·1 answer
  • This reaction forms triphenylmethanol from benzophenone. How could you use infrared spectroscopy to show that the benzophenone h
    5·1 answer
  • Which element has the element configuration 1s2 2s2 2p4
    9·1 answer
  • Is -2 degrees Fahrenheit warmer or is -17 degrees fahrenheit?
    10·1 answer
  • Which of the following is composed mostly of ice?
    12·1 answer
  • How does the valence bond theory describe a covalent bond formation?
    5·1 answer
  • Dot and cross diagram for oxygen ion
    7·1 answer
  • A single bond represents 4 electrons.<br> True<br> O False
    15·1 answer
  • Provide the correct IUPAC name for Sr(OH)2 - 7H20.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!