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If 250 g of calcium chlorate decomposes into calcium chloride and oxygen what mass of oxygen would be produced
1 answer:
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La aspirina se prepara haciendo reaccionar ácido salicílico con exceso de anhídrido etanoico. En un experimento, 50.05 g de ácido salicílico se convirtieron en 55.45 g de aspirina. ¿Cuál fue el porcentaje de rendimiento?
<em>In English:</em>
Aspirin is prepared by reacting salicylic acid with excess ethanoic anhydride. In one experiment, 50.05 g of salicylic acid was converted to 55.45 g of aspirin. What was the yield percentage?
Answer:
el rendimiento porcentual para la cantidad dada de ácido salicílico es 84.99 %
<em>In English:</em>
<em>the percent yield for the given amount of salicylic acid is </em><em>84.99%</em>
<em></em>
Explanation:
La ecuación química equilibrada para la reacción se puede escribir como:
C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + HC₂H₃O₂
Para la reacción mostrada arriba; El reactivo limitante de la reacción es el ácido salicílico. Ahora; calcular el porcentaje de rendimiento; se espera que primero determinemos el rendimiento teórico de la reacción.
Entonces; la fórmula para calcular el porcentaje de rendimiento:
El rendimiento teórico se determina de la siguiente manera:
50.05 g * 1 mol / 138.21 g / mol de C₇H₆O₃ * 1 mol de C₉H₈O₄ / 1 mol de C₇H₆O₃ * 180.157 g / mol de C₉H₈O₄ = 65.24 g de C₉H₈O₄
Porcentaje de rendimiento
Porcentaje de rendimiento = 84.99%
Por lo tanto, el porcentaje de rendimiento para la cantidad dada de ácido salicílico es 84.99%
<em>In English:</em>
<em>The balanced chemical eqaution for the reaction can be written as:</em>
<em>C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + HC₂H₃O₂</em>
<em>For the reaction shown above; The limiting reactant from the reaction is salicylic acid. Now; to calculate the percentage yield ; we are expected to first determine the theoretical yield of the reaction. </em>
<em>So; the formula for calculating the percentage yield </em><em> </em>
<em />
<em>The theoretical yield is determined as follows:</em>
<em>50.05 g * 1 mol/ 138.21 g/mol of C₇H₆O₃ * 1 mol of C₉H₈O₄/ 1 mol of C₇H₆O₃ * 180.157 g/mol of C₉H₈O₄ = 65.24 g of C₉H₈O₄ is produced</em>
<em />
<em>Percentage yield </em><em />
<em>Percentage yield = 84.99%</em>
<em />
<em>Thus, the percent yield for the given amount of salicylic acid is </em><em>84.99%</em>
<u>Answer:</u> 72 grams of water will be produced.
<u>Explanation:</u>
To calculate the number of moles, we use the formula:
....(1)
Mass of propane = 44 grams
Molar mass of propane = 44 grams
Putting values in above equation, we get:
For the reaction of combustion reaction of propane, the equation follows:
By Stoichiometry of the reaction,
1 mole of propane produces 4 moles of water.
So, 1 mole of propane will produce = of water.
Now, to calculate the amount of water, we use equation 1, we get:
Molar mass of water = 18 g/mol
Mass of water produced = 72 grams
Hence, 72 grams of water will be produced.