Answer:
The three statements are true
Explanation:
For the reaction:
I₂O₅(s) + 5CO(g) → I₂(s) + 5CO₂(g)
State oxidation of iodine in I₂O₅ is:
5 O²⁻ = 10⁻
As you have 2 I and the molecule has no charge, <em>oxidation state of I is +5</em>.
The carbon in CO has an oxidation state of +2 and in CO₂ is +4. That means <em>the carbon is oxidized</em>
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An oxidizing agent is a substance that produce the oxidation of the agent that reacts with this one. CO is oxidized because of I₂O₅ is producing its oxidation being <em>the oxidizing agent</em>
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Thus,<em> the three statements are true</em>.
Answer:
Three orbitals
Explanation:
The electronic configuration of carbon is given as follows;
1s²2s²2p²
Therefore, out of the six electrons of the carbon atoms, 4 fill the 1s and 2s orbitals with 2 electrons each, while the two remaining electrons are situated in the 2p orbital, with the electrons in the 2p orbital will remain unpaired such that they will have similar quantum numbers in accordance with Pauli exclusion principle.
No. Of protons = mass no. - no. Of neutrons
No. Of protons = 67 - 37
= 30
No. Of electrons = 28
Zinc will have 30 protons and 28 electrons. So, it will have +2 charge
Symbol - Zn^+2
