Answer:
1. True WA > WB > WC
Explanation:
In this exercise they give work for several different configurations and ask that we show the relationship between them, the best way to do this is to calculate each work separately.
A) Work is the product of force by distance and the cosine of the angle between them
WA = W h cos 0
WA = mg h
B) On a ramp without rubbing
Sin30 = h / L
L = h / sin 30
WB = F d cos θ
WB = F L cos 30
WB = mf (h / sin30) cos 30
WB = mg h ctan 30
C) Ramp with rubbing
W sin 30 - fr = ma
N- Wcos30 = 0
W sin 30 - μ W cos 30 = ma
F = W (sin30 - μ cos30)
WC = mg (sin30 - μ cos30) h / sin30
Wc = mg (1 - μ ctan30) h
When we review the affirmation it is the work where there is rubbing is the smallest and the work where it comes in free fall at the maximum
Let's review the claims
1. True The work of gravity is the greatest and the work where there is friction is the least
2 False. The job where there is friction is the least
3 False work with rubbing is the least
4 False work with rubbing is the least
P = m*v
7.5 = m*15
m = 7.5/15 = 0.5 kg
Mechanical energy is the answer
Answer:
Explanation:
assume
M= mass of Mars
m=mass of phobos
r=orbital radius
T=period
we can apply F=ma to this orbital motion (considering the cricular motion laws)
where,
and a=rω^2
where ω=
and G is the universal gravitational constant.
G = 6.67 x 10-11 N m2 / kg2
Answer:
1.56 m/s
Explanation:
For East direction, the 6 blocks is equivalent to 6*100=600 m
For West direction, 8 blocks is equivalent to 8*100=800 m
Speed is given by s=d/t where s is speed, d is distance covered and t is time taken
Total distance is 600+800=1400m
Time taken is 15 mins, converted to seconds will be 15*60=900 s
Speed, s=1400/900=1.5555555555555 m/s rounded off as 1.56 m/s
