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Nastasia [14]
3 years ago
10

It takes 258 kJ/mol to eject electrons from a certain metal surface. What is the longest wavelength of light (nm) that can be us

ed to eject electrons from the surface of this metal via the photoelectric effect?
Chemistry
1 answer:
Sergeeva-Olga [200]3 years ago
3 0

<u>Answer:</u> The wavelength of light that can be used is 464 nm

<u>Explanation:</u>

We are given:

Energy of the electrons = 258 kJ/mol

This is the energy of the 1 mole of electrons

To calculate the energy of 1 electron, we divide the energy by Avogadro's number:

\text{Energy of 1 electron}=\frac{E}{N_A}

N_A=6.022\times 10^{23}

E=258kJ/mol=2.58\times 10^5J/mol     (Conversion factor:  1 kJ = 1000 J)

Putting values in above equation, we get:

\text{Energy of 1 electron}=\frac{2.58\times 10^5}{6.022\times 10^{23}}=4.28\times 10^{-19}J

To calculate the energy of one photon, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

Energy of 1 electron = 4.28\times 10^{-19}J

Putting values in above equation, we get:

4.28\times 10^{-19}J=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{\lambda}\\\\\lambda=\frac{6.625\times 10^{-34}\times 3\times 10^8m/s}{4.28\times 10^{-19}}=4.64\times 10^{-7}m

Converting this to nano meters, we use the conversion factor:

1m=10^9nm

So, 4.64\times 10^{-7}m\times \frac{10^9nm}{1m}=464nm

Hence, the wavelength of light that can be used is 464 nm

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