A girl is sitting in a sled sliding horizontally along some snow (there is friction present). The mass of the girl is 29.8 kg an
d the mass of the sled is 10.3 kg.
The force of friction acting on the sled as it slides is -123 N.
If the sled was initially moving at 13.3 m/s at t=0, how far will it slide before the sled stops?
1 answer:
Answer:
28.81 m
Explanation:
Ff = -123
m * a = -123
(29.8+10.3) * a = -123
a = -123/40.1 = -3.07
We know,
v^2 = u^2 + 2as
0^2 = 13.3^2 + 2*(-3.07)*s
s = 176.89/6.14 = 28.81
[ If there's a problem with the solution, pleaase let me know ]
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