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Greeley [361]
3 years ago
13

A girl is sitting in a sled sliding horizontally along some snow (there is friction present). The mass of the girl is 29.8 kg an

d the mass of the sled is 10.3 kg.
The force of friction acting on the sled as it slides is -123 N.

If the sled was initially moving at 13.3 m/s at t=0, how far will it slide before the sled stops?
Physics
1 answer:
jonny [76]3 years ago
6 0

Answer:

28.81 m

Explanation:

Ff = -123

m * a  = -123

(29.8+10.3) * a = -123

a = -123/40.1 = -3.07

We know,

v^2 = u^2 + 2as

0^2 = 13.3^2 + 2*(-3.07)*s

s = 176.89/6.14 = 28.81

[ If there's a problem with the solution, pleaase let me know ]

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You buy a 75 watt light bulb. the label means that
alukav5142 [94]
The label means that the bulb will consume 75 joules of electrical energy in 1 sec
4 0
3 years ago
An avant-garde composer wants to use the Doppler effect in his new opera. As the soprano sings, he wants a large bat to fly towa
Allisa [31]

Answer:

     v’= 9.74 m / s

Explanation:

The Doppler effect is due to the relative movement of the sound source and the receiver of the sound, in this case we must perform the exercise in two steps, the first to find the frequency that the bat hears and then the frequency that the audience hears that also It is sitting.

Frequency shift heard by the murciela, in case the source is still and the observer (bat) moves closer

        f₁ ’= f₀ (v + v₀)/v

         

Frequency shift emitted by the speaker in the bat, in this case the source is moving away from the observer (public sitting) that is at rest

         f₂’= f₁’ v/(v - vs)

           

Note that in this case the bat is observant in one case and emitter in the other, called its velocity v’

            v’= vo = vs

Let's replace

           f₂’= f₀   (v + v’)/v   v/(v -v ’)

           f₂’= f₀   (v + v’) / (v -v ’)

           (v –v’ ) f₂’ / f₀ = v + v ’

           v’ (1+ f₂’ /f₀) = v (f₂’/fo - 1)

           v’ (1 + 1.059) = 340 (1.059 - 1)

           v’= 20.06 / 2.059

           v’= 9.74 m / s

6 0
3 years ago
describe the charge, mass and the location of each subatomic particle and the role each plays in determining the properties of a
Harrizon [31]

Explanation :

An atom is a smallest particle of matter. An atom consists of protons, neutrons and electrons. These are three subatomic particles.

Protons are positively charged species while neutrons are negatively charged species. Electrons revolves around an atom.

Charge :

The charge of an electron is negative or -1.6\times 10^{-19} \ C

The charge of proton is +e or   1.6\times 10^{-19} \ C

Neutron has no charge.

Mass :

Atomic mass of electron is 9.1\times10^{-31}\ Kg

Atomic mass of proton is 1.67\times10^{-27}\ Kg

Atomic mass of neutron is 1.67\times10^{-27}\ Kg

Both protons and neutrons are located inside the nucleus at the center.

Charge, atomic mass and location determines the properties of an atom. Atomic mass tells about the number of protons and neutrons inside an atom.  Electric charge tells us the number of electrons gain or lost.

6 0
3 years ago
A proton is moving in a circular orbit of radius 20 cm under a uniform magnetic field 0.3 t perpendicular to the velocity of the
Vladimir [108]

Answer:

v = 5.75 x 10⁶ m/s

Explanation:

The radius (r) of the circular orbit taken by a charged particle is related to its speed perpendicular to a magnetic field of strength B, and is given by

r = \frac{mv}{qB}       --------------(i)

Where,

q = charge of the particle

m = mass of the particle

Making v subject of the formula in equation (i) above gives

v = \frac{qBr}{m}  -------------------(ii)

Given;

r = 20cm = 0.2m

B = 0.3T

v = unknown

q = charge of proton = 1.6 x 10⁻¹⁹ C

m = mass of the proton = 1.67 x 10⁻²⁷kg

Substitute the values of m, q, B and r into equation (ii) above to get;

v = \frac{1.6 * 10^{-19} * 0.3 * 0.2} {1.67*10^{-27} }

Solving for v gives:

v = 5.75 x 10⁶ m/s

Therefore, the velocity of the proton is 5.75 x 10⁶ m/s

4 0
3 years ago
_____ has a longer wavelength than _____.
victus00 [196]

Answer:

B

Explanation:

its b ok ok bye

7 0
2 years ago
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